在React 2中使用Google登录按钮 [英] Using google sign in button with react 2

问题描述

这与将google登录按钮与react ，但就我而言，可接受的答案无法解决.

This is essentially the same question as Using google sign in button with react but the accepted answer does not solve it in my case.

我有一个反应成分:

var LoginButton = React.createClass({

onSignIn: function(googleUser) {
  console.error(" user signed in");                                                                                                                                                               
},

componentDidMount: function() {
  console.log('component has mounted');
    gapi.signin2.render('g-signin2', {
      'scope': 'https://www.googleapis.com/auth/plus.login',
      'width': 200,
      'height': 200,
      'longtitle': true,
      'theme': 'dark',
      'onsuccess': this.onSignIn
    })
},

render: function() {
  return (
     <div className="g-signin2"/>
  );
}
}

但是，即使登录成功完成，也不会调用onSignIn函数.实际上，我为渲染自定义登录按钮指定的所有选项均不存在(即正方形和深色主题)，所以我猜由于<div>的类，它正在渲染默认按钮.

But while the sign-in works successfully, the onSignIn function is never called. In fact none of the options I specify for rendering the custom signin button are present (i.e. the square shape and dark theme), so I guess it's rendering a default button because of the <div>'s class.

我当前正在同步加载库，因为否则触发componentDidMount时gapi不在范围内.

I'm currently loading the library synchronously because otherwise gapi is not in scope when componentDidMount is triggered.

我看到的另一个选项是Google建议使用<script src="https://apis.google.com/js/platform.js?onload=renderButton" async defer></script>并将我的渲染包装在函数中.但是，要么要么必须将此脚本加载到组件内部，要么我必须找到一种方法，使该函数在范围内作为index.html中的回调传递，这两种方法都不是很好的解决方案.

The other option I see would be google's recommendation of using <script src="https://apis.google.com/js/platform.js?onload=renderButton" async defer></script> and wrapping my render in a function. But then either this script has to be loaded inside the component, or else I have to find a way that this function is in scope to be passed as a callback in index.html, neither of which seem like a good solution.

如何显示自定义登录按钮而不是默认登录按钮?

How can I get the custom login button to be rendered instead of the default one?

推荐答案

此hack现在可以解决问题了...

This hack does the trick for now...

在我的index.html中，当库加载时触发一个自定义事件:

In my index.html I trigger a custom event when the library loads:

<script src="https://apis.google.com/js/platform.js?onload=triggerGoogleLoaded" async defer></script>
<script type="text/javascript">
  function triggerGoogleLoaded() {
    window.dispatchEvent(new Event('google-loaded'));
  }
</script>

和我的react组件现在看起来像这样:

and my react component now looks like this :

var LoginButton = React.createClass({

  onSignIn: function(googleUser) {
      console.log("user signed in"); // plus any other logic here
  },

  renderGoogleLoginButton: function() {
    console.log('rendering google signin button')
    gapi.signin2.render('my-signin2', {
      'scope': 'https://www.googleapis.com/auth/plus.login',
      'width': 200,
      'height': 50,
      'longtitle': true,
      'theme': 'light',
      'onsuccess': this.onSignIn
    })
  },

  componentDidMount: function() {
    window.addEventListener('google-loaded',this.renderGoogleLoginButton);
  },

  render: function() {
    let displayText = "Sign in with Google";
    return (
       <div id="my-signin2"></div>
    );
  }

});

请注意，渲染的<div>具有"my-signin2"作为id而不是class.

note that the rendered <div> has "my-signin2" as an id not a class.

这篇关于在React 2中使用Google登录按钮的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！