检查按钮是否可用?如果不等5秒钟再检查一次? [英] check if a button is available? if not wait 5 seconds and check again?

问题描述

基本上，我正在尝试查看当前是否可以单击按钮.如果没有，我想再试一次.因此，我需要某种goto函数以返回到我的代码的较早代码行.虽然我怀疑我写得很差，但可以做得容易得多.

Basically I'm trying to see if a button is able to be clicked at the moment. If not I would like to try again. So I need some kind of a goto function to return to an earlier line of my code. Although I suspect I written this extremely poorly and it could have been done much easier.

try {
    driver.findElement(By.xpath("//button[@id='btn_ok']")).click();
}catch (Exception e) {
    driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
}   

对于上下文，这是有问题的按钮元凶.

for context, here is the button culprit in question.

<button type="submit" value="ok" name="s1" id="btn_ok" class="green">

推荐答案

您可以使用流利的方法来等待.这将检查按钮是否每5秒钟单击一次，持续30秒钟.您可以根据需要调整时间.尝试使用此代码，并给出反馈是否有效.

You can use fluent wait for this. This will check for the button to be clickable at every 5 seconds for 30 seconds. You can adjust the time according to your need. Try this code and give feedback whether it worked or not.

 Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)                           
                .withTimeout(30, TimeUnit.SECONDS)          
                .pollingEvery(5, TimeUnit.SECONDS)          
                .ignoring(NoSuchElementException.class);
        WebElement clickseleniumlink = wait.until(new Function<WebDriver, WebElement>(){

            public WebElement apply(WebDriver driver ) {
                return driver.findElement(By.xpath("//button[@id='btn_ok']"));
            }
        });
        clickseleniumlink.click();

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