Grails/Groovy正则表达式-如何使用(?i)使所有内容不区分大小写? [英] Grails/Groovy regular expression- how to use (?i) to make everything case insensitive?
问题描述
我使用以下RegEx:
I use the following RegEx:
url (blank:false, matches: /^(https?:\/\/)(?:[A-Za-z0-9]+([\-\.][A-Za-z0-9]+)*\.)+[A-Za-z]{2,40}(:[1-9][0-9]{0,4})?(\/\S*)?/)
我想添加(?i)以使所有内容均不区分大小写.我应该如何添加呢?
I want to add (?i) to make everything case insensitive. How should I add this?
推荐答案
我可以确认正则表达式开头的(?i)
使其不区分大小写.
I can confirm the (?i)
at the beginning of the regex makes it case insensitive.
无论如何,如果您的目的是减少正则表达式的长度,则可以使用groovy 美元斜线形式.它允许您不转义斜杠/
(转义字符变为$
).
Anyway, if your purpose is to reduce the regex length you can use the groovy dollar slashy string form. It allows you to not escape slashes /
(the escape char becomes $
).
此外:
-
POSIX字符
\p{Alnum}
是[0-9a-zA-Z]
的紧凑等效项(通过这种方式,您可以完全避免使用(?i)
).
the POSIX chars
\p{Alnum}
is the compact equivalent of[0-9a-zA-Z]
(this way you can avoid to use the(?i)
at all).
从char类[\-\.]
->中删除不需要的反斜杠. [-.]
(当破折号是第一个或最后一个元素,并且点在字符组中始终是文字时,则不是强制性的.)
remove unneeded backslashed dash from char class [\-\.]
-> [-.]
(it's not mandatory when the dash is the first or the last element and also the dot is always literal inside a character group).
从协议部分中删除不需要的圆括号
remove unneeded round brackets from the protocol section
在以下版本中,我利用美元斜线字符串和自由行正则表达式标志(?x)
的多行支持:
In the following version I take advantage of the multiline support of dollar slashy string and the free-spacing regex flag (?x)
:
$/(?x)
^ # start of the string
https?:// # http:// or https://, no need of round brackets
( # start group 1, have to be a non capturing (?: ... ) but is less readable
\p{Alnum}+ # one or more alphanumeric char instead of [a-zA-Z0-9]
([.-]\p{Alnum}+)* # zero or more of (literal dot or dash followed by one or more [a-zA-Z0-9])
\. # a literal dot
)+ # repeat the group 1 one or more
\p{Alpha}{2,40} # between 2 and 40 alphabetic chars [a-zA-Z]
(:[1-9][0-9]{0,4})? # [optional] a literal colon ':' followed by at least one non zero digit till 5 digits
(/\S*)? # [optional] a literal slash '/' followed by zero or more non-space chars
/$
一刀切的精简版:
$/^https?://(\p{Alnum}+([.-]\p{Alnum}+)*\.)+\p{Alpha}{2,40}([1-9][0-9]{0,4})?(/\S*)?/$
如果必须使用斜杠版本,则等效:
If you must use the slashy version this is an equivalent:
/^https?:\/\/(?:\p{Alnum}+([.-]\p{Alnum}+)*\.)+\p{Alpha}{2,40}(:[1-9][0-9]{0,4})?(\/\S*)?/
测试所有这些正则表达式的代码片段:
A snippet of code to test all these regex:
def multiline_pattern = $/(?x)
^ # start of the string
https?:// # http:// or https://, no need of round bracket
( # start group 1, have to be a non capturing (?: ... ) but is less readable
\p{Alnum}+ # one or more alphanumeric char, instead of [a-zA-Z0-9]
([.-]\p{Alnum}+)* # zero or more of (literal dot or dash followed by one or more [0-9a-zA-Z])
\. # a literal dot
)+ # repeat the group 1 one or more
\p{Alpha}{2,40} # between 2 and 40 alphabetic chars [a-zA-Z]
(:[1-9][0-9]{0,4})? # [optional] a literal colon ':' followed by at least one non zero digit till 5 digits
(/\S*)? # [optional] a literal slash '/' followed by zero or more non-space chars
/$
def compact_pattern = $/^https?://(\p{Alnum}+([.-]\p{Alnum}+)*\.)+\p{Alpha}{2,40}(:[1-9][0-9]{0,4})?(/\S*)?/$
def slashy_pattern = /^https?:\/\/(?:\p{Alnum}+([.-]\p{Alnum}+)*\.)+\p{Alpha}{2,40}(:[1-9][0-9]{0,4})?(\/\S*)?/
def url1 = 'https://www.example-test.domain.com:12344/aloha/index.html'
def notUrl1 = 'htxps://www.example-test.domain.com:12344/aloha/index.html'
def notUrl2 = 'https://www.example-test.domain.com:02344/aloha/index.html'
assert url1 ==~ multiline_pattern
assert url1 ==~ compact_pattern
assert url1 ==~ slashy_pattern
assert !( notUrl1 ==~ compact_pattern )
assert !( notUrl1 ==~ slashy_pattern )
assert !( notUrl1 ==~ slashy_pattern )
assert !( notUrl2 ==~ compact_pattern )
assert !( notUrl2 ==~ slashy_pattern )
assert !( notUrl2 ==~ slashy_pattern )
这篇关于Grails/Groovy正则表达式-如何使用(?i)使所有内容不区分大小写?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!