如何在python中直观地堆叠多个折线图? [英] How do I visually stack multiple line graphs above each other in python?

问题描述

我在创建需要多个线图的绘图时遇到了麻烦.

I was having trouble creating a plot I need which has multiple line graphs.

我想要的是一种在彼此之上绘制每个图的方法(例如，一个基线的y = 5，我希望下一个基线的y = 10)，而且这些图中的每一个都必须阻止一个它上面.

What I want is a way to graph each of these above the other (say one has a baseline of y=5 I want the next to have a baseline of y=10) and also each of these graphs must block the one above it.

因此，这不可避免地看起来像Joy Joys Divisions Unknown Pleasures的封面: http://cococubed.asu.edu/images/unknown_pleasures/unknown_pleasures.jpg

So this will inevitably look like the cover to Joy Divisions Unknown Pleasures here: http://cococubed.asu.edu/images/unknown_pleasures/unknown_pleasures.jpg

除了倒置的颜色，我也想要一个使用python或numpy或matplotlib的答案.

Except inverted colors and I also would like an answer that utilizes python or numpy or matplotlib.

推荐答案

这是一种方法.关键是要使用fill_between函数，并以一定的边距(在本例中为i*2)偏移每条绘制的线.另外，绘图必须从顶部开始，因此是[range:]切片中的[::-1].

Here's one way. The key point is to use fill_between function and offset each plotted line with some margin (i*2 in this case). Also, plotting has to start from the top, hence the [::-1] in the arange slice.

t=linspace(-2*pi, 2*pi, 1000)
for i in arange(1, pi, 0.01)[::-1]:
    left = exp(-(t + (i - 1) * 2*pi)**2) * cos(t * i)**2 - 1
    right = exp(-(t - (i - 1) * 2*pi)**2) * cos(t * i)**2 - 1 
    vertical_offset = i*2
    fill_between(t, vertical_offset + left + right, facecolor='white')

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