如何删除边并在两个顶点之间添加新边? [英] How to remove an edge and add a new edge between two vertices?

问题描述

我试图放置一条边线，并在两个顶点之间添加一条新边线.我该如何在Tinkerpop3中做到这一点?

I'm trying to drop an edge and add a new edge between two vertices. How do I do that in Tinkerpop3?

def user = g.V().has("userId", 'iamuser42').has("tenantId", 'testtenant').hasLabel('User'); 
user.outE("is_invited_to_join").where(otherV().has("groupId", 'test123')).drop();
def group = g.V().has("groupId", 'test123').has("tenantId", 'testtenant').hasLabel('Group').next();
user.addEdge("is_member_of", group);

这是我在gremlin shell上遇到的错误:

This is the error I get on gremlin shell:

No signature of method: org.apache.tinkerpop.gremlin.process.traversal.dsl.graph.DefaultGraphTraversal.addEdge() is applicable for argument types: (java.lang.String, com.thinkaurelius.titan.graphdb.vertices.CacheVertex) values: [is_member_of, v[8224]]

谢谢.

推荐答案

Gremlin控制台教程对此问题进行了一些讨论.您没有在遍历遍历.请考虑以下内容:

The Gremlin Console tutorial discusses this issue a bit. You are not iterating your traversal. Consider the following:

gremlin> graph = TinkerFactory.createModern()
==>tinkergraph[vertices:6 edges:6]
gremlin> g = graph.traversal()
==>graphtraversalsource[tinkergraph[vertices:6 edges:6], standard]
gremlin> person = g.V().has('name','marko')
==>v[1]

太好了！人员Vertex存储在人员"变量中...或者是

Great! The person Vertex is stored in the "person" variable...or is it?

gremlin> person.class
==>class org.apache.tinkerpop.gremlin.process.traversal.dsl.graph.DefaultGraphTraversal

显然它不是Vertex. "person"是Traversal，控制台会这样看待它并为您进行迭代，这就是为什么您得到"v

Apparently it is not a Vertex. "person" is a Traversal, the console sees it as such and iterates it for you which is why you get "v1" in the output. Note that the traversal is now "done":

gremlin> person.hasNext()
==>false

您需要将Traversal迭代到变量中-在这种情况下，请使用next():

You need to iterate the Traversal into your variable - in this case, using next():

gremlin> person = g.V().has('name','marko').next()
==>v[1]
gremlin> person.class
==>class org.apache.tinkerpop.gremlin.tinkergraph.structure.TinkerVertex

请注意，由于使用的是现在将Vertex用作Traversal的脚本，因此脚本中的行会进一步出现问题，因此此行:

Note that you will have further problems down the line in your script because you are using what will now be a Vertex as a Traversal, so this line:

user.outE("is_invited_to_join").where(otherV().has("groupId", 'test123')).drop();

现在将失败，并出现类似的错误，因为Vertex将没有outE().您将需要执行以下操作:

will now fail with a similar error because Vertex will not have outE(). You would need to do something like:

g.V(user).outE("is_invited_to_join").where(otherV().has("groupId", 'test123')).drop();

如果您想添加一条边并以相同的遍历将旧的边放下，则可以执行以下操作:

If you would like to add an edge and drop the old one in the same traversal, you could do something like this:

gremlin> graph = TinkerFactory.createModern()
==>tinkergraph[vertices:6 edges:6]
gremlin> g = graph.traversal()
==>graphtraversalsource[tinkergraph[vertices:6 edges:6], standard]
gremlin> g.V(1).outE('knows')
==>e[7][1-knows->2]
==>e[8][1-knows->4]
gremlin> g.V(1).as('a').outE().as('edge').inV().hasId(2).as('b').addE('knew').from('a').to('b').select('edge').drop()
gremlin> g.V(1).outE('knew')
==>e[12][1-knew->2]
gremlin> g.V(1).outE('knows')
==>e[8][1-knows->4]

可以说，这可能不如将其分为两个或多个单独的遍历那样可读，但是可以做到.

Arguably, that might not be as readable as breaking it into two or more separate traversals, but it can be done.

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