如何grep文件中存在特定的十六进制字节? [英] How to grep for presence of specific hex bytes in files?

问题描述

我的Web应用程序正在显示一些异常输出(不应该存在的unicode字符，等等).我能想到的最好的办法是，我以某种方式在源代码中的某个地方引入了一个坏字符，但我不知道在哪里.

My web app is displaying some bizarro output (unicode characters that shouldn't be there, etc.). The best I can reckon is that somehow I introduced a bad char somewhere in the source, but I can't figure out where.

我找到了此答案，指出我可以执行以下操作:

I found this answer that states I can do something like:

grep -obUaP "<\x-hex pattern>" .

当我将Unicode字符从浏览器复制到我的 Bless 十六进制编辑器中时，它会告诉我char的确切字节是:

When I copy the unicode char out of the browser and into my Bless hex editor, it tells me that the exact bytes of the char are:

15 03 01 EF BF BD 02 02

15 03 01 EF BF BD 02 02

如何格式化<\xhex pattern>以匹配我需要的确切字节.我试过了:

How can I format <\xhex pattern> to match the exact bytes that I need. I tried:

grep -obUaP "<\x-15 03 01 EF BF BD 02 02>" .

但这不起作用.有想法吗?

But that doesn't work. Thoughts?

推荐答案

再次检查帖子. FrOsT不包含'<'和'>'在他实际的grep命令中.他只用克拉括了一个例子.他的实际陈述是这样的:

Check the post again. FrOsT is not including the '<' and '>' in his actual grep command. He only used the carats to enclose an example statement. His actual statement looks like this:

"\x01\x02"

不是:

"<\x01\x02>"

我的计算机上有一个以以下行开头的C源文件:

I have a C source file on my computer that begins with the line:

#include <stdio.h>

我跑步时

grep -obUaP '\x69\x6E\x63\x6C\x75\x64\x65' io.c

我知道

1:include

即，行号后跟 only 匹配模式的字符串.

That is, the line number followed by only the string matching the pattern.

您可能要运行

man grep

并找出所有这些选项的含义.

and find out what all those options mean.

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