更新:网格PYTHON [英] UPDATE: Mesh grid PYTHON

问题描述

我正在处理一个网格网格，该网格具有一个光标，当您输入分配的数字时该光标会移动.我能够使光标移动，唯一的问题是我希望它在光标移动时打印出更新后的坐标的位置(例如，如果光标向下移动一个块，则新位置应是(0，-1)).

I'm working on a mesh grid that has a cursor that moves when you enter the assigned number. I was able to get the cursor to move, the only problem I'm having is that I want it to print out the location of the updated coordinates as the cursor moves, (ex. if the cursor moves down one block the new location should be (0,-1)).

x = y = 0
size = int(input('Enter grid size: '))
print(f'Current location: ({x},{y})')

def show_grid(x, y):
    for i in range(size):
        for j in range(size):
            if i == y and j == x:
                print('+', end=' ')
            else:
                print('.', end=' ')
        print()
show_grid(x,y)

def show_menu():
    print('-- Navigation --')
    print('2 : Down')
    print('8 : Up')
    print('6 : Right')
    print('4 : Left')
    print('5 : Reset')
    print('0 : EXIT')
    return 0
show_menu()

choice = int(input('Enter an option: '))            ####current location not updating
def move(x, y, choice):
    if choice == 2:     # down
        show_grid(x, y+1)
    elif choice == 8:   # up
        show_grid(x, y-1)
    elif choice == 4:   # left
        show_grid(x-1, y)
    elif choice == 6:   # right
        show_grid(x+1, y)
    elif choice == 5:   # reset to (0,0)
        show_grid(x, y)
    elif choice == 1:
        print(choice, 'Not a valid input. Try again.')
        show_grid(x, y)
    elif choice == 3:
        print(choice, 'Not a valid input. Try again.')
        show_grid(x, y)
    elif choice == 7:
        print(choice, 'Not a valid input. Try again.')
        show_grid(x, y)
    elif choice == 9:
        print(choice, 'Not a valid input. Try again.')
        show_grid(x, y)
move(x, y, choice)



#main program
while True:
    choice = show_menu()
    if choice == 0:
        print(f'Current location: ({x},{y})')
        break
    else:
        x,y = move(x,y,choice)
    print(f'Current location: ({x},{y})')
    if 0 <= x < size and 0 <= y < size:  # inside the board
        print(f'Current location: ({x},{y})')
    else:  # outside the board
        print('The new location is off the board.')
        break
    print('Exit the program')

推荐答案

在定义move()的内部，您要先使用return(即，退出函数)，然后再调用show_grid()

Inside your definition of move(), you are using return (ie, exiting the function) before you get to the part that calls show_grid()

无需返回，只需将x，y设置为所需的值即可.另外，我注意到另一件事可能会导致您出现问题.您使用option决定下一步，然后使用option = show_menu().但是，您定义show_menu()的方式始终返回0.为了使options包含用户的输入，您应该更改show_menu()的定义方式，或者更改option的分配方式.

instead of returning, just set x, y to whatever they need to be. Also, I noticed one other thing that may be causing you problems. You use option to decide what to do next, and option = show_menu(). But the way you've defined show_menu(), it always returns 0. In order for options to contain the user's input, you should either change the way show_menu() is defined, or change the way option is assigned.

在OP更新后进行 这是我看到的问题

Edit after OP's update: Here are the problems that I see

1. 在功能show_menu()中:您从未要求用户提供任何输入.您总是返回0.
2. 在功能move()中:x和y未更新.您会将更新后的x和y传递给show_grid()，但此后将不使用它们.
3. 您当前在#main program中是break.

1. In your function show_menu(): you never asked for any input from the user. You are always returning 0.
2. In your function move(): x and y are not updated. You're passing the updated x and y to show_grid(), but after that they are not used.
3. You currently break out of your #main program if choice == 0.

这是您要解决我上面提到的每个问题的工作:

Here's what you'll have to do to fix each of the problems I mentioned above:

1. 在函数show_menu()中:要求用户输入并返回而不是0.
2. 将您当前传递给show_grid()和y的新值返回.
3. 删除break.如果您没有先固定#1就这样做，则会陷入无限循环-但是如果先固定#1，它将等待用户输入.

1. In your function show_menu(): ask for the user's input and return it instead of 0.
2. Return the new values of x and y that you are currently passing to show_grid().
3. Remove break. If you do this without fixing #1 first you'll end up in an infinite loop - but if you fix #1 first it will wait for user input.

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