机器人在网格中的位置和方向 [英] Position and orientation of robot in a grid

问题描述

我想制作一个10x10的网格并将机器人放置在位置(10,1)(左下).我希望该机器人能够向前移动，向左/向右旋转并拾取/放置网格中的对象.当放置在任何位置时，网格中应该有数字，可以显示在该位置放置了多少个对象，就像这样:

I want to make a 10x10 grid and put the robot in position (10,1) (bottom left). I want this robot to be able to move forward, turn left/right and to pick up/put objects in a grid. When put in any position, there should be number in a grid which shows how many objects is put in this position, just like this:

..........
...1......
..2.......
....3.....
..........
..........
......9...
.....4....
.........1
..........

我们不会在网格中看到机器人.我有两节课.班级机器人:

We will not see the robot in a grid. I have two classes. Class Robot:

public class Robot {

private Area area;
private Robot rob;

public Robot(Area area){
    this.area = area;
    rob = new Robot(area);
}

public void Right(){

}
public void Left(){

}
public void Forward(){

}
public void Put(){

}
public void PickUp(){

}
public (?) getPosition(){ // should return robot's position

}
}

班级区域:

private int numberOfObjects;
private Robot robot;
private static final int X = 10;
private static final int Y = 10;
private Object [][] area; // grid

public Area(){ // defines a grid and robot
    area = new Area[X][Y];
    for(int a=0;a<X;a++){
        for(int b=0;b<Y;b++)
            area[a][b]=".";
    }

    numberOfObjects = 0; // grid is initially empty
    Area ar = new Area();
    robot = new Robot(ar);
}

public void Put(int x,int y){ // put the object to position (x,y)
    area[x][y]=numberOfObjects++;
}

public void PickUp(int x,int y){ // pick up the object in position (x,y)
    if(area[x][y]!=null){
        area[x][y]=numberOfObjects--;
    }
}

public void PrintAGrid(){
    for(int r=0;r<X;r++){
        for(int c=0;c<Y;c++)
        System.out.print(area[r][c]+" ");
     System.out.println();
    }
    System.out.println();
}
}

如何将机器人放置在(10,1)位置?如何声明和设置其方向(即在右侧)?我想写其他方法会很容易，所以我不关注它.

How can I put the robot in position (10,1)? How can I declare and set its orientation (i.e. on the right)? I guess it will be easy to write other methods, so I do not focus on it.

推荐答案

您的代码有几个问题.

1. 为什么在类Robot中有一个Robot的实例?您根本没有使用过该实例！
2. private Object [][] area;应该是int[][] area.您总是在其中保存int，对吧?
3. 如果我正确理解您的要求，则您对pick和put的实现不正确.

1. Why do you have an instance of Robot inside the class Robot? You have not used that instance at all!
2. private Object [][] area; should be int[][] area. You always save int in this, right?
3. If I understand your requirements correctly, Your implementation of pick and put is not correct.

---

在这里可以帮助您解决问题.我不得不考虑是否应该将Robot放在Grid中，或者应该是另一种方式.我以Robot中的Grid结尾. 可能是Grid可能是单身人士.

---

Here is a help how you can solve the problems. I had to think several times if Robot should be in Grid or it should be the other way. I ended up with Grid in Robot. May be Grid could be a singleton.

这是我们的Grid

public class Grid {
    private int[][] numberOfObjects = new int[10][10];

    public void put(int x, int y) {
        numberOfObjects[y][x]++;
    }

    public void pick(int x, int y) {
        numberOfObjects[y][x]--;
    }
}

您可以用Point替换参数int x, int y.

这是机器人

public class Robot {
    private static final int NORTH = 0, EAST = 1, SOUTH = 2, WEST = 3;
    private int direction;
    private int x, y;

    private Grid grid;

    public Robot(Grid grid) {
        this.x = 0;
        this.y = 0;

        this.grid = grid;
        direction = NORTH;
    }

    public void right() {
        direction++;
        if (direction == 4) {
            direction = 0;
        }
    }

    public void left() {
        direction--;
        if (direction == -1) {
            direction = 3;
        }
    }

    public void forward() {
        if (direction == NORTH) {
            y--;
        } else if (direction == SOUTH) {
            y++;
        } else if (direction == EAST) {
            x++;
        } else if (direction == WEST) {
            x--;
        }
    }

    public void put() {
        grid.put(x, y);
    }

    public void pick() {
        grid.pick(x, y);
    }
}

这篇关于机器人在网格中的位置和方向的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！