Groovy:如何测试属性访问是否成功? [英] Groovy: how to test if a property access will be successful?

问题描述

我有一个变量Object foo，它不为null.我想使用foo.bar，但前提是它不会以没有这样的属性:针对类的酒吧:无论如何"轰炸我.

I have a variable Object foo, which is not null. I want to use foo.bar, but only if it won't bomb me with 'No such property: bar for class: Whatever'.

我应该如何进行以下测试:

How should I do the following test:

if (/*test-here*/) {
  use(foo.bar)
}

推荐答案

使用object.hasProperty(propertyName).如果属性存在，这将返回真实值(属性引用). object.metaClass.hasProperty(instance, propertyName)也是可能的.使用object.respondsTo(methodName)测试方法是否存在.

Use object.hasProperty(propertyName). This will return a truthy value (the property reference) if the property exists. Also object.metaClass.hasProperty(instance, propertyName) is possible. Use object.respondsTo(methodName) to test for method existence.

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