地图中的Groovy对象属性 [英] Groovy object properties in map

问题描述

不必从像这样的对象中声明地图中的所有属性:

Instead of having to declare all the properties in a map from an object like:

prop1: object.prop1

难道不能像下面那样将对象放在那里吗?还是实现这一目标的合适方法是什么?

Can't you just drop the object in there like below somehow? Or what would be a proper way to achieve this?

results: [
    object, 
    values: [
        test: 'subject'
    ]
]

推荐答案

object.properties也将为您提供class

object.properties will give you a class as well

您应该能够:

给出您的POGO对象:

Given your POGO object:

class User {
    String name
    String email
}

def object = new User(name:'tim', email:'[e-mail]')

编写一种方法来检查该类并从中获取非合成属性:

Write a method to inspect the class and pull the non-synthetic properties from it:

def extractProperties(obj) {
    obj.getClass()
       .declaredFields
       .findAll { !it.synthetic }
       .collectEntries { field ->
           [field.name, obj."$field.name"]
       }
}

然后，将地图分散到您的结果地图中:

Then, map spread that into your result map:

def result = [
    value: true, 
    *:extractProperties(object)
]

给你

['value':true, 'name':'tim', 'email':'[e-mail]']

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