Groovy提取字符前的子字符串 [英] Groovy extract substring before character

问题描述

我有一堆像这样的字符串

I have a bunch of strings like

asdf v1.0
jkl v3.04

我所有的字符串都是一组字符，后跟一个空格，然后是"v"，然后是一个数字.我想从每个字符串中提取"v"之前的部分以及在"v"之前的空格字符，以便:

all my strings are a group of characters followed by a space then 'v' then a number. I want to extract from each string, the part that comes before the 'v' and the space character preceeding the 'v' so that:

asdf v1.0 becomes 'asdf'
jkl v3.04 becomes 'jkl'

在这方面需要一些帮助.我尝试了takeWhile { it != 'v' }，但最终在结果字符串中包含了我不想要的'v'之前的空格.

just need some help with this. I tried takeWhile { it != 'v' } but that ends up including the space before the 'v' in the result string which I don't want.

推荐答案

您可以简单地提取子字符串:

You can simply extract the substring:

input.substring(0, input.lastIndexOf(" v"))

要获得v之后的零件:

input.substring(input.lastIndexOf(" v") + 2)

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