正则表达式将组匹配到PowerShell中的字符串 [英] Regex match group to string in PowerShell

问题描述

我有一个正则表达式，它对字符串进行搜索并创建两个匹配组:

I have a regex that does a search on a string and creates two match groups:

    if ($BASICEDITMESSAGECONTENT -match '(?sm)(^.*?</title>)(.*)')
    {
        if ($matches.Count -ge 3)
        {
            $BASICEDITMESSAGECONTENT = "$matches[1]$SCRIPTREFERENCE$matches[2]"
            echo $BASICEDITMESSAGECONTENT
            ...
        }
    }

当我将其回显时，将得到以下输出:

When I echo it back, I get the following output:

System.Collections.Hashtable[1]<MYSCRIPTREFERENCE>System.Collections.Hashtable[2]

我在字符串中不需要这样的System.Collections.Hashtable值，我只想从该正则表达式分组中找到匹配文本的实际值字符串.我该如何实现?

I don't want System.Collections.Hashtable values like this in the string, I just want the actual value string of the matching text from that regex grouping. How can I make it happen?

例如，当我使用echo $matches[1]时，它将显示正则表达式组的实际值，而不是System.Collections.Hashtable[1].

For example, when I use echo $matches[1], it displays the actual value of the regular expression group, not System.Collections.Hashtable[1].

推荐答案

您需要使用 sub-表达式索引哈希表:

You need to use sub-expressions to index the hashtables:

$BASICEDITMESSAGECONTENT = "$($matches[1])$SCRIPTREFERENCE$($matches[2])"

注意每个索引周围的$(...).您希望将字符串文字作为表达式求值的所有部分都放在$(...)内.否则，PowerShell只会扩展变量名，并将[1]之类的其他内容视为普通文本.

Notice the $(...) around each index. All parts of string literals that you want evaluated as expressions need to be placed inside $(...). Otherwise, PowerShell will only expand the variable names and treat other stuff like [1] as just normal text.

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