PHP GuzzleHttp.如何使用params进行发布请求? [英] PHP GuzzleHttp. How to make a post request with params?

问题描述

如何使用GuzzleHttp(5.0版)发出发布请求.

How to make a post request with GuzzleHttp( version 5.0 ).

我正在尝试执行以下操作:

I am trying to do the following:

$client = new \GuzzleHttp\Client();
$client->post(
    'http://www.example.com/user/create',
    array(
        'email' => '[e-mail]',
        'name' => 'Test user',
        'password' => 'testpassword'
    )
);

但是我得到了错误:

PHP致命错误:带有消息没有方法可以处理电子邮件配置密钥"的未捕获异常'InvalidArgumentException'

PHP Fatal error: Uncaught exception 'InvalidArgumentException' with the message 'No method can handle the email config key'

推荐答案

尝试一下

$client = new \GuzzleHttp\Client();
$client->post(
    'http://www.example.com/user/create',
    array(
        'form_params' => array(
            'email' => '[e-mail]',
            'name' => 'Test user',
            'password' => 'testpassword'
        )
    )
);

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