正确地使用(guzzle)6发送(POST)xml [英] Proper way to send (POST) xml with guzzle 6

问题描述

我想用发送大量xml文件的狂饮来进行发布.我没有找到一个例子.

I want to perform a post with guzzle sending an xml file. I did not find an example.

到目前为止，我要做的是:

What I 've done so far is :

$xml2=simplexml_load_string($xml) or die("Error: Cannot create object");
use    GuzzleHttp\Client;
use GuzzleHttp\Psr7\Request;
$client = new Client();
//
$request = new Request('POST', $uri, [ 'body'=>$xml]);
$response = $client->send($request);
 //
//$code = $response->getStatusCode(); // 200
//$reason = $response->getReasonPhrase(); // OK
 //
 echo $response->getBody();

无论我尝试什么，我都会得到错误-1，这意味着xml无效. 我发送的XML虽然通过了在线验证，并且有效为％100

No matter what I try I get back error -1 which means that xml is not valid. XML that I send passes online validation though and is valid %100

请帮助.

推荐答案

经过一些实验，我已经弄清楚了.这是我的解决方案，以防有人死胡同.

After some experiments, I have figured it out. Here is my solution in case someone reaches a dead end.

$request = new Request(
    'POST', 
    $uri,
    ['Content-Type' => 'text/xml; charset=UTF8'],
    $xml
);

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