HAML:仅在条件为true时创建容器/包装器元素 [英] HAML: Create container/wrapper element only if condition is true

问题描述

远射，但我想知道是否有任何办法可以做这样的事情:

Longshot, but I'm wondering if there's any way to do something like this:

%p # ONLY SHOW THIS IF LOCAL VARIABLE show_paras IS TRUE
  = name

换句话说，它总是在其中显示内容，但是只有在(某些条件)为true时，它才会在其周围包装一个容器.

In other words, it always shows the content inside, but it only wraps a container around it if (some-condition) is true.

推荐答案

您可以使用原始html，但随后必须在开头和结尾处都使用if语句:

You could use raw html, but then you'd have to have the if statement both at the beginning and end:

- if show_paras
  <p>
= name
- if show_paras
  </p>

假设您要做的不只是= name，还可以使用部分:

Assuming you're doing more than just = name, you could use a partial:

- if show_paras
  %p= render "my_partial"
- else
  = render "my_partial"

您还可以使用HAML的surround(尽管有点杂乱):

You could also use HAML's surround (though this is a little messy):

- surround(show_paras ? "<p>" : "", show_paras ? "</p>" : "") do
  = name

最后，我可能根本不会尝试忽略p标记，而只是使用CSS类来设置两种不同的p样式以符合我想要的方式:

Finally, what I would probably do is not try to omit the p tag at all, and just use CSS classes to set up two different p styles to look the way I want:

%p{:class => show_paras ? "with_paras" : "without_paras"}
  = name

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