有什么办法可以看到原始类型的HashCode吗? [英] Any way to see HashCode of primitive types?

问题描述

搞砸基本D.S ....我读到，没有用于原始类型int的hashCode()方法，如果在int上调用，它将抛出错误

Mugging up basic D.S....I read that, no hashCode() method for primitive type int is available and if called on int, it will throw error

错误:无法取消引用int

error: int cannot be dereferenced

这是否意味着如果int n = 10，则其HashCode也将为10?

Does this means that if int n = 10 then its HashCode will also be 10??

如果我仍然需要在下面的程序中查看int的hascode，是否有一种方法可以查看它，例如Integer Wrapper ???

If i still need to see hascode for int in below program, is there a method to see it, like Integer Wrapper???

public static void main(String []args){
       String me = "hello";
       int n = 10;

       int h1 = me.hashCode();
       int h2 = n.hashCode();

       System.out.println(h1);
       System.out.println(h2);
     }

推荐答案

您不能在原始类型上调用方法.

You cannot invoke methods on primitive types.

n被声明为int.它没有方法.

n is declared as int. It does not have methods.

像

如果我仍然需要在下面的程序中查看int的hascode

If i still need to see hascode for int in below program

您可以创建一个Integer对象并获取其hashCode()

You could create an Integer object and get its hashCode()

Integer.valueOf(n).hashCode()

Integer#hashCode()的实现方式为

public int hashCode() {
    return value;
}

其中value是它要包装的int值.

这是否意味着如果int n = 10，则其HashCode也将为10?

Does this means that if int n = 10 then its HashCode will also be 10??

int没有哈希码.但是，其Integer包装器将具有其包装的int的值.

The int doesn't have a hashcode. Its Integer wrapper will however have the value of the int it's wrapping.

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