哈希表映射-更新值 [英] Hash Table Map - updating values

问题描述

我只是使用哈希表来记住图像中出现哪些互补色.

I am just using a hash table to remember which complementary colours appear in an image.

无论如何，我得到了当前值计数:

Anyway so I get the current value count:

Float count = complementaryColour.get(complementaryString[1] + " and " + colourName);

现在我想更改计数，所以我这样做:

and now I want to change count, so I do:

count += (Float)((frequency/width*height)*total_distance);

放回去

complementaryColour.put(complementaryString[1] + " and " + colourName, count);

可悲的是，它不喜欢这样！它说我需要创建一个浮点数，然后查看将其放回哈希表中的那一行，它说它无法解析为变量.

Yet sadly it doesn't like this! It says I need to create a float count, and then when I look at the line putting it back in the hashtable it says it cannot be resolved to a variable.

我以前看过这件事，但是只有当我们有Integer count ...然后count ++时才可以完成；然后可以将其返回到哈希表！

I have seen this done before, but only when we have Integer count... then count++; this can then be returned to the hashtable!

推荐答案

根据您的问题，您的Hashtable如下所示.

As per your question your Hashtable is like below.

Map <String , Float> complementaryColour=new Hashtable<String, Float >();

尝试

float f=(float) ((frequency/width*height)*total_distance);
lCount+=f;

这篇关于哈希表映射-更新值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！