如何使用php渲染远程图像? [英] How can I render a remote image with php?

问题描述

以下是jpg:http://i.stack.imgur.com/PIFN0.jpg

假设我要从/img.php?file_name=PIFN0.jpg

这就是我要尝试的工作方式:

Here's how I'm trying to make this work:

/sample.php

<p>Here's my image:</p>
<img src="/img.php?file_name=PIFN0.jpg">

/img.php

<?php
    $url = 'http://i.stack.imgur.com/' . $_GET['file_name'];
    header('Content-type: image/jpeg');
    imagejpeg($url);
?>

我希望/sample.php显示图像.但这是行不通的.我得到的只是一张破碎的图像.我在做什么错了?

I would expect /sample.php to show the image. But this doesn't work. All I get is a broken image. What am I doing wrong?

推荐答案

使用imagecreatefromjpeg:

<?php
    $url = 'http://i.stack.imgur.com/' . $_GET['file_name'];
    header('Content-type: image/jpeg');
    imagejpeg(imagecreatefromjpeg($url));
?>

参考: http://php.net/manual /en/function.imagecreatefromjpeg.php

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