如何在Masm代码中写字母起始的十六进制数字? [英] How do I write letter-initiated hexadecimal numbers in masm code?

问题描述

我目前正在编辑由MASM代码组成的几个宏. 它们看起来都与此类似:

I am currently editing several macros consisting of MASM code. They all look similar to this:

Primary MACRO
Key 0Bh,'0'
Key 29h,15h
Key 03h,'2'
Key 06h,'5'
Key 0Ch,'+'
Key 0Dh,'´'
Key 1Bh,'¨'
Key 2Bh,27h
Key 35h,'-'
Key 34h,'.'
Key 33h,','
Key 56h,'<'
ENDM

我注意到我可以用以下格式写由十六进制数字(由字符0-9开始)的十六进制数字:02h，12h，5Ah等. 但是，如果我尝试以相同的方式写字母起始的十六进制数字(即ABh，CAh，DFh等)，则会出现错误.我已经尝试过0xBA，0xFE等格式，但是它也不起作用.

I have noticed that I can write hexadecimal numbers which are initiated by (begin with) character 0-9 in the following format: 02h, 12h, 5Ah, etc. However, if I try to write letter-initiated hexadecimal numbers in the same way (that is, like ABh, CAh, DFh, etc.), I get an error. I have tried the format 0xBA, 0xFE, etc., but it doesn't work either.

在这种情况下，谁能告诉我写字母起始的十六进制数字所使用的正确格式?

Can anyone tell me the correct format to use for writing letter-initiated hexadecimal numbers in this case?

推荐答案

十六进制AB的正确格式为0ABh.

The correct format for hex AB is 0ABh.

您需要以数字开头的原因是，以便汇编程序可以轻松地将其与标签或符号(例如ABh)区别开.

The reason you need to start it with a digit is so the assembler can easily distinguish it from a label or symbol such as ABh.

也不必担心它具有三位数的事实.因此，它不会神奇地变成十二位数字，使用的位数将取决于您使用的寻址模式.

And don't worry about the fact it has three digits. It doesn't magically turn into a twelve-bit number because of that, the number of bits used will depend on the addressing modes you're using.

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