Excel VBA中的十六进制到ASCII转换错误 [英] Hex to ascii conversion error in Excel VBA

问题描述

我发现以下所述的将十六进制转换为文本的功能.它对于大多数十六进制转换为文本的功能都很好，但是给出异常结果.

I have found below stated function for conversion of hex to text.It works fin for most of hex to text conversions but give abnormal result.

例如，十六进制值为:

050003d40201414c4552542d42656c6f772038353435206966204e462054726164657320666f722031352d3230206d696e75746573202c77617463682050414e49432050414e4943207570746f20353439332d2d383437360d0a0d0a53656c6c204549434845522061742032343931302e2e2e73746f706c6f7373732032353

我使用hex2text函数得到的结果= |

Result i get on using hex2text Function = |

正确的结果应该是这样的:

Correct Result should have been something like:

ALERT-Below 8545 if NF Trades for 15-20 minutes ,watch PANIC PANIC upto 5493--8476........

(注意:我使用了hex2ascii转换网站 http://www .rapidtables.com/convert/number/hex-to-ascii.htm 以获得正确的结果)

(Note: I used hex2ascii conversion website http://www.rapidtables.com/convert/number/hex-to-ascii.htm to obtain correct results)

我的Hex2text函数是:

Public Function HexToText(text As Range) As String
    Dim i As Integer
    Dim DummyStr As String

    For i = 1 To Len(text) Step 2
       DummyStr = DummyStr & Chr(Val("&H" & (Mid(text, i, 2))))
       DoEvents
    Next i

    HexToText = DummyStr
End Function

推荐答案

如Alex所述，前6个字节是导致此问题的原因.

As Alex has stated, the first 6 bytes are causing the issue.

您可以通过更改ForNext循环从第13个字符开始:

You could either start at the 13th character by changing the ForNext loop:

 For i = 13 To Len(text) Step 2

或者您可以过滤任何ASCII码小于32的字符.

Or you could filter any characters with ASCII code lower than 32 out..

If Val("&H" & (Mid(Text, i, 2))) > 31 Then DummyStr = DummyStr & Chr(Val("&H" & (Mid(Text, i, 2))))

或将其替换为(例如)空格.

Or replace them with (for instance) a space..

If Val("&H" & (Mid(Text, i, 2))) > 31 Then 
   DummyStr = DummyStr & Chr(Val("&H" & (Mid(Text, i, 2))))
Else
   DummyStr = DummyStr & " "
End If

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