Lucene休眠搜索NumericRangeQuery< Float>在使用@NumericField定义的字段上不起作用 [英] Lucene hibernate search NumericRangeQuery<Float> not working on field defined with @NumericField

查看:112
本文介绍了Lucene休眠搜索NumericRangeQuery< Float>在使用@NumericField定义的字段上不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

除此问题外,我使用休眠搜索4.1.0均具有良好的结果. 我正在尝试在定义的列中执行范围搜索:

I use hibernate search 4.1.0 with good results except for this problem. I´m trying to perform a range search in a column defined:

@Field(name = "startTime", store = Store.YES)
@NumericField
public Float startTime;

我存储了一个startTime = 0.0f的项目;

I have stored an item with startTime = 0.0f;

然后我尝试执行范围查询:

then I try to perform a range query:

NumericRangeQuery<Float> rangeQuery = NumericRangeQuery.newFloatRange(
                "startDate", -100000.0f, +100000.0f, true, true);
FullTextQuery fullTextQuery = fullTextEntityManager
                .createFullTextQuery(rangeQuery, Item.class);
results = fullTextQuery.getResultList();

第一:我没有结果.

第二:使用lukeall检查索引,我看到只是存储了似乎是toString()的东西(也通过其他实验判断),这看起来不正常...

Second: Inspecting the index with lukeall, I see simply stored what seems to be the toString() [judging by other experiments too], which looks not normal...

我觉得我缺少什么,任何帮助将不胜感激. 谢谢

I feel like I´m missing something, any help would be appreciated. Thanks

推荐答案

Hibernate论坛首先,为了其他读者而在此处重新发布:

Replied on the Hibernate forums first, reposting here for the sake of other readers:

第一:我认为您定位的字段名错误;字段名称是startTime,而不是startDate.在这种情况下,由于您是直接包装Lucene查询,因​​此我们无法检查其有效性.

first: I think you're targeting the wrong field name; the field name is startTime, not startDate. In this case since you are wrapping a Lucene Query directly we can't check for it's validity.

:在卢克中看到的是Store.YES

second: what you see in Luke is the result of Store.YES

这篇关于Lucene休眠搜索NumericRangeQuery&lt; Float&gt;在使用@NumericField定义的字段上不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆