在Hive中,如何组合多个表以产生包含对象数组的单行? [英] In Hive, how to combine multiple tables to produce single row containing array of objects?
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问题描述
我有两个表,如下所示:
I have two tables as follows:
users table
==========================
| user_id name age |
|=========================
| 1 pete 20 |
| 2 sam 21 |
| 3 nash 22 |
==========================
hobbies table
======================================
| user_id hobby time_spent |
|=====================================
| 1 football 2 |
| 1 running 1 |
| 1 basketball 3 |
======================================
第一个问题:我想做一个Hive查询,该查询可以返回以下格式的行:
First question: I would like to make a single Hive query that can return rows in this format:
{ "user_id":1, "name":"pete", "hobbies":[ {hobby: "football", "time_spent": 2}, {"hobby": "running", "time_spent": 1}, {"hobby": "basketball", "time_spent": 3} ] }
第二个问题:嗜好表是否如下:
========================================
| user_id hobby scores |
|=======================================
| 1 football 2,3,1 |
| 1 running 1,1,2,5 |
| 1 basketball 3,6,7 |
========================================
是否有可能获得行输出,其中scores是输出中的列表,如下所示:
Would it be possible to get the row output where scores is a list in the output as shown below:
{ "user_id":1, "name":"pete", "hobbies":[ {hobby: "football", "scores": [2, 3, 1]}, {"hobby": "running", "scores": [1, 1, 2, 5]}, {"hobby": "basketball", "scores": [3, 6, 7]} ] }
推荐答案
我能够找到第一个问题的答案
I was able to find the answer to my first question
select u.user_id, u.name,
collect_list(
str_to_map(
concat_ws(",", array(
concat("hobby:", h.hobby),
concat("time_spent:", h.time_spent)
))
)
) as hobbies
from users as u
join hobbies as h on u.user_id=h.user_id
group by u.user_id, u.name;
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