Symfony2,Doctrine扩展树:生成类似“树"的下拉列表,选择列表 [英] Symfony2,Doctrine Extensions Tree : Generating a "tree"-like dropdown Select list
问题描述
我有一个使用Doctrine Tree Extension的使用Tree体系结构构建的类别表 看起来像这样
I have a Categories table, built with Tree architecture, using Doctrine Tree Extension and it looks something like this
id parent_id title lft lvl rgt root
864 (NULL) Movies 1 0 18 864
865 864 Packs 2 1 3 864
866 864 Dubbed 4 1 5 864
在视觉上是这样的:
Movies
|
|
|->Packs
|->Dubbed
现在我想生成用于添加评论的表单,并为每部电影的下拉列表加载类别,因此我的电影评论中具有form-type-class
now i want to generated form for adding reviews , and loading categories as dropdown list for each movie, so i have in my movie-review form-type-class
public function buildForm(FormBuilder $builder, array $options)
{
$builder->add('name');
$builder->add('file');
$builder->add('cover');
$builder->add('category','entity', array('class'=>'Tracker\MembersBundle\Entity\Category', 'property'=>'title', ));
}
会生成一个普通的下拉菜单,如下所示:
which generates a normal dropdown menu like this:
如何配置菜单设置,这样它会生成像这样的 Tree-Like-下拉选择?
how can i configure my menu settings, so it generates a Tree-Like-dropdown select like this?
推荐答案
我不确定这是个好主意:用户将无法输入自己的选择.
I'm not sure this is a good idea : users won't be able to type in their choice.
尚未测试此解决方案,但它应该可以工作:
Haven't tested this solution, but it should work :
首先,您可以按root和lft值对这三个值进行排序以正确显示它,因此添加一个查询构建器:
First, you can sort the three by root and lft value to display it properly, so add a query builder:
'query_builder' => function($er) {
return $er->createQueryBuilder('c')
->orderBy('c.root', 'ASC')
->addOrderBy('c.lft', 'ASC');
},
然后,您需要向您的实体添加getIndentedTitle
方法:
Then, you need to add a getIndentedTitle
method to your entity:
public function getIndentedTitle() {
return str_repeat("--", $this->lvl).$this->title;
}
最后,在构建表单时,在选项中添加一个属性选项,以显示虚拟属性indentedTitle而不是title:
Finally, add a property option to your options when you build the form, to display the virtual property indentedTitle instead of title :
'property' => 'indentedTitle'
请参阅: http://symfony.com/doc/current /reference/forms/types/entity.html
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