如何删除空的html标记(包含空格和/或其html代码) [英] How to remove empty html tags (which contain whitespaces and/or their html codes)

问题描述

需要preg_replace的正则表达式.

Need a regex for preg_replace.

该问题未在另一个问题"中回答因为并非我要删除的所有标签都不都是空的.

This question wasn't answered in "another question" because not all tags I want to remove aren't empty.

我不仅要从HTML结构中删除空标签，还必须删除包含换行符，空格和/或其html代码的标签.

I have not only to remove empty tags from an HTML structure, but also tags containing line breaks as well as white spaces and/or their html code.

可能的代码是:

< br/> & nbsp; & thinsp; & ensp; & emsp; &#8201; &#8194; &#8195;

<br /> &nbsp; &thinsp; &ensp; &emsp; &#8201; &#8194; &#8195;

在删除匹配标签之前:

<div> 
  <h1>This is a html structure.</h1> 
  <p>This is not empty.</p> 
  <p></p> 
  <p><br /></p>
  <p> <br /> &;thinsp;</p>
  <p>&nbsp;</p> 
  <p> &nbsp; </p> 
</div>

在删除匹配的标签之后:

AFTER removing matching tags:

<div> 
  <h1>This is a html structure.</h1> 
  <p>This is not empty.</p> 
</div>

推荐答案

您可以使用以下内容:

<([^>\s]+)[^>]*>(?:\s*(?:<br \/>|&nbsp;|&thinsp;|&ensp;|&emsp;|&#8201;|&#8194;|&#8195;)\s*)*<\/\1>

并替换为''(空字符串)

请参见演示

注意:这也适用于具有属性的空html标签.

Note: This will also work for empty html tags with attributes.

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