Symfony 2错误页面响应 [英] Symfony 2 error page response

问题描述

我有一个用Angular编写的SPA和Symfony2 API一起使用.我希望错误响应(例如500)以json格式而不是HTML重新调整，而HTML根据文档

I have a SPA written in Angular used with a Symfony2 API. I want error responses like 500 to be retuned in json format rather than the HTML which according to the docs here is supported out the box.

对于错误页面，它首先会查找给定格式和状态代码的模板(例如error404.json.twig)；

For error pages, it first looks for a template for the given format and status code (like error404.json.twig);

我只是找不到任何地方向我展示如何明确指定我想要json格式.我以为拥有请求标头'Accept':'application/json'是它在谈论的内容，但是它不能如另一个问题

I just cannot find anywhere that shows me how to explicitly specify that I want the json format. I thought having the request header 'Accept': 'application/json' was what it was talking about however that does not work as mentioned in another question here

如何让throw new NotFoundHttpException('Could not find....');返回与默认HTML相对的json响应.

How can I have throw new NotFoundHttpException('Could not find....'); return a json response opposed to the default HTML.

推荐答案

您可以通过两种方式设置格式:

You can set format in two ways:

路径路径中的

1. {_format}占位符

在您的控制器中调用$request->setRequestFormat('json')方法

In your controller call $request->setRequestFormat('json') method

---

routeName:
    path: /news/{id}/show.{_format}
    defaults:
        _controller: BundleName:Controller:method
        format: json
    requirements:
        _format: json|xml|html # you can remove xml & html, if you no have there formats

这篇关于Symfony 2错误页面响应的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！