向MQ发送消息时如何删除默认的Spring JMS Template头? [英] How to remove default Spring JMS Template headers when sending a message to an MQ?

问题描述

使用Java/Spring与WebSphere MQ交互并尝试向其发送消息，Spring会继续向其添加以下标头信息:

Using Java/Spring to interact with a WebSphere MQ and trying to send a message to it, Spring keeps adding the following header information to it:

RFH Ì ¸MQSTR ¸ <mcd><Msd>jms_text</Msd></mcd> <jms><Dst>queue:///MY.QUEUE.INFORMATION.TEST</Dst><Rto>queue:///MY.QUEUE.INFORMATION.TEST</Rto><Tms>123456789</Tms><Dlv>2</Dlv></jms>BEGINNING_OF_MY_PAYLOAD

我将如何删除所有内容并仅发送我的有效载荷?可以在上面的代码段中将我的有效负载称为BEGINNING_OF_MY_PAYLOAD.

How would I remove everything and only send my payload? One could refer to my payload in the snippet above as BEGINNING_OF_MY_PAYLOAD.

这是我正在使用的功能:

Here's the function I'm using:

public void sendMessage(final String text) {
        this.jmsTemplate.send(new MessageCreator() {
            @Override
            public Message createMessage(Session session) throws JMSException {
                Message message = session.createTextMessage(text);
                destination = session.createQueue("MY.QUEUE.INFORMATION.TEST");
                springJmsConsumer.setDestination(destination);
                message.setJMSReplyTo(destination);
                return message;
            }
        });
    }

推荐答案

弄清楚了.每当我们想从发送到WebSphere MQ的Spring JMS消息中删除标头时，请始终使用以下内容:

Figured it out. Anytime we want to remove headers from our Spring JMS message being sent out to a WebSphere MQ, always use the following:

this.jmsTemplate.convertAndSend("queue:///YOUR.QUEUE.NAME.HERE?targetClient=1", text);

所以现在我的函数如下:

So now my function looks like:

public void send(String text) {
        this.jmsTemplate.convertAndSend("queue:///MY.QUEUE.INFORMATION.TEST?targetClient=1", text);
}

这篇关于向MQ发送消息时如何删除默认的Spring JMS Template头?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！