如果带有条件的语句已设置并且比较不能一起使用 [英] If statement with condition isset and comparing not working together

问题描述

我在制作if语句时遇到问题:

I'm having a problems with making if statements:

<?php if (isset($detail) == 1) { ?>
    // code if detail variable exists and is equal to 1
<?php } else { ?>
    // code if detail variable doesn't exist or is not equal 1
<?php }?>

由于某种原因，该条件不起作用.我该如何解决if条件，这样才能正常工作?

For some reason this condition doesn't work. How could I fix the if condition, so it will work?

推荐答案

isset是一个布尔运算符，它返回TRUE或FALSE.您无需将其与1进行比较.

isset is a boolean operator which returns TRUE or FALSE. You don't need to compare it to 1.

if( isset($detail) )

作为一个旁注，仅因为设置了变量，并不意味着它不为空.您可能只想检查一下它是否为空:

As a side note, just because the variable is set, does not mean it's not empty. You may want to just check that it's not empty:

if( !empty($detail) )

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