没有其他“如果"的“其他" [英] 'else' without a previous 'if'

问题描述

我才刚刚开始学习C编程，所以我还不是真正的高级.忍受我！

I am just beginning to learn C programming, so I am not really on an advanced level. Bear with me!

我有这段代码，我想很容易理解我要做什么.但是我收到一个错误消息，说最后一个else之前没有if调用.

I have this piece of code, and I guess that it is pretty easy to understand what I am trying to do. However I get an error saying the last else is called without an if before it.

我怀疑问题是我在if和else之间的if-else语句.你们将如何解决?

I suspect that the problem is my if-else statement inbetween the if and else. How would you guys solve it?

int talet;
scanf("%d", &talet);

int i = 1;
while (i <= 99) {
  int a; {
    if (i % talet == 0 || talet == (i / 10) % 10 || talet == i % 10) {
      if (talet % 10 == 0)
        printf("\n");
      else
        continue;
    }
    printf("burr ");
    else
      printf("%d ", i);
  }
  i = i + 1;
}

推荐答案

问题出在括号里.缩进对于了解在何处打开和关闭括号很重要

The problem is with your brackets. Indenting is important to understand where to open and close your brackets

int talet;
scanf("%d",&talet);

int i=1;
while(i<=99)
{
int a;

    if (i%talet==0 || talet==(i/10)%10 ||talet==i%10)
    {
             if (talet%10==0)
                  printf("\n");
             else
                  continue;

        printf("burr ");
    }
    else
    {
        printf("%d ",i);
    }
    i=i+1;
}

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