@ bot.message_handler()中的lamda函数在Telebot python中无法正常工作 [英] lamda funtion in @bot.message_handler() not working properly in telebot python

问题描述

我试图在python脚本中实现以下代码行，以使用Telebot构建电报机器人.

I tried to implement the following line of code in python script for a telegram bot building using telebot.

@bot.message_handler(func=lambda msg:True if msg.text.startswith('/test'))
def test_start(message):
    msg=bot.send_message(message.chat.id,'This is feature is under developement')

上面的代码给我一个语法错误.

Above code gives me a syntax error.

@bot.message_handler(func=lambda msg:True if msg.text.startswith('/test') else False)
def test_start(message):
    msg=bot.send_message(message.chat.id,'This is feature is under developement')

此代码解决了语法错误，但仍然不能满足我的要求.当用户发送"/test some text"时，我想识别它并在此之后执行一些操作.

This code solves the syntax error, but still, it doesn't do what I want it to do. When a user sends '/test some text' I want to identify this and do some actions after that.

我对python比较陌生，这是我第一次使用telebot和lambda函数.所以请帮助我

I am relatively new to python and this is my first time using telebot and lambda functions. So please help me in

1. 确定为什么第一个代码给我语法错误.
2. 如何正确地以('/test')开始. 提前非常感谢您.

1. identifying why the 1st code gave me a syntax error.
2. How to implement this startswith('/test') properly. Thank you so much in advance.

推荐答案

因为三元运算符具有特定的语法，因此必须遵循:

Because ternary operator has a specific syntax, that has to be followed:

<value if True> if <condition> else <value if False>

您在第一个示例中所做的是:

What you did in the first sample is:

<value if True> if <condition>

您也不必像以前那样做

True if msg.text.startswith('/test') else False

.startswith()单独返回bool.

不清楚装饰器是做什么的，但是为什么不只在函数内部执行检查呢?

It's unclear what decorator does, but why don't you just perform the check inside of the function?

@bot.message_handler
def test_start(message):
    if msg.startswith('/test'):
        msg=bot.send_message(message.chat.id,'This is feature is under developement')

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