从目标总是和独立执行蚂蚁行动 [英] Execute Ant action always and independently from target

问题描述

有没有指定一个像＆LT行动的方式;复制＆GT;在让每一个构建文件被蚂蚁（无论这就是所谓的目标）？

Is there a way to specify actions like <copy> in an Ant buildfile that get executed every time the build file gets read by ant (regardless of the target which is called)?

的背景是：我想要的* .properties文件从模板自动生成时，它不是present。我知道，我可以指定一个目标而做到这一点，然后将其包含在依赖关系树的根，但也许还有一个更优雅的解决方案。因为实际上这个问题是一个比较复杂的：其中的* .properties文件中读出由其他构建文件导入，我不希望他们之间交叉引用的目标蚂蚁文件

The background is: I want a *.properties-file to be automatically created from a template when it's not present. I know, I could specify a target which does this and then include it at the root of the dependency-tree but maybe there is a more elegant solution. Because actually the problem is a bit more complex: the ant file where the *.properties-file is read-out is imported by other build files and I don't want to cross-reference targets between them.

我希望我充分的解释我的问题。在问题的情况下毫不犹豫问。

I hope I explained my problem sufficiently. In cases of questions do not hestitate to ask.

这是我第一次在这里发帖。希望你能帮助 - 来自德国的问候，本

This is my first posting here. Hope you can help - Greetings from Germany, Ben.

推荐答案

只要把code。在文件的顶部，目标定义之外。

Just put the code at the top of the file, outside of a target definition.

<project name="myproject" default="mytarget" basedir=".">

  <echo message="Hello there." />

  <target name="mytarget">
    <!-- Do stuff. -->
  </target>

  <target name="myothertarget">
    <!-- Do other stuff. -->
  </target>

</project>

在这种情况下，回声将获得的任何目标前执行一次，无论是调用了哪些目标。

In this case the echo will get executed once before any target, regardless of which target is invoked.

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