将切片索引存储为对象 [英] Store Slice Index as Object
本文介绍了将切片索引存储为对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
说我有一个列表列表的列表,等等……有些深度:
Say I have a list of lists of lists etc... of some depth:
ExampleNestedObject = numpy.ones(shape = (3,3,3,3,3))
一般来说,我可以通过写得到一个元素:
In general I can get an element by writing:
#Let:
#a, b, c, d, e -> are integers
print ExampleNestedObject[a][b][c][d][e]
#numpy also happens to allow:
print ExampleNestedObject[(a,b,c,d,e)]
#python in general allows:
print ExampleNestedObject[a,b,:,d,e]
我的问题是->如何将索引"a,b,:,d,e"存储为对象?
My question is -> how can I store the index "a,b,:,d,e" as an object?
SomeSliceChoice = a,b,:,d,e
print ExampleNestedObject[SomeSliceChoice]
推荐答案
诀窍是将索引对象视为切片对象的元组.
The trick is to think of an index object as a tuple of slice objects.
示例1:
Object[1,2,:] == Object[(1,2,slice(None,None,None))]
示例2:
WantedSliceObject = (1,2,slice(None,None,None), 4,5)
Object[1,2,:,4,5] == Object[WantedSliceObject]
请注意'''slice的语法:
Note the syntax of '''slice:
#slice(start, stop[, step])
#1 == slice(1, 2, 1)
WantedSliceObject2 = (
slice(1, 2, 1),
slice(2, 2, 1),
slice(None,None,None),
slice(4, 2, 1),
slice(5, 2, 1)
)
#WantedSliceObject2 == WantedSliceObject
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