我可以在python类中使用两个init函数吗? [英] Can I have two init functions in a python class?
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问题描述
我正在从 http://janmatuschek.de/LatitudeLongitudeBoundingCoordinates#Java 移植一些地理定位Java代码(如下所示)到python.可以使用两个函数(fromDegrees或fromRadians)来初始化它.我以为我可以做类似的事情
I'm porting some geolocation java code from http://janmatuschek.de/LatitudeLongitudeBoundingCoordinates#Java (shown below) to python. It can be initialized using two functions (fromDegrees or fromRadians). I thought I could do something like
class geoLocation:
_radLat = 0
_radLong = 0
_degLat = 0
_degLong = 0
def fromDegrees(lat, long):
#set _radLat, _radLong, _degLat, _degLong
def fromRadians(lat, long):
#set _radLat, _radLong, _degLat, _degLong
...
但这似乎不是最佳选择，因为我两次设置了_radLat，_radLong，_degLat和_degLong的值.我可以定义两个初始化函数吗?最好的方法是什么?
But that does not seem optimal since I set the values for _radLat, _radLong, _degLat and _degLong twice. Can I define two init functions? What's the best way to do that?
谢谢
/**
* <p>Represents a point on the surface of a sphere. (The Earth is almost
* spherical.)</p>
*
* <p>To create an instance, call one of the static methods fromDegrees() or
* fromRadians().</p>
*
* <p>This code was originally published at
* <a href="http://JanMatuschek.de/LatitudeLongitudeBoundingCoordinates#Java">
* http://JanMatuschek.de/LatitudeLongitudeBoundingCoordinates#Java</a>.</p>
*
* @author Jan Philip Matuschek
* @version 27 May 2010
*/
public class GeoLocation {
private double radLat; // latitude in radians
private double radLon; // longitude in radians
private double degLat; // latitude in degrees
private double degLon; // longitude in degrees
private static final double MIN_LAT = Math.toRadians(-90d); // -PI/2
private static final double MAX_LAT = Math.toRadians(90d); // PI/2
private static final double MIN_LON = Math.toRadians(-180d); // -PI*2
private static final double MAX_LON = Math.toRadians(180d); // PI*2
private GeoLocation () {
}
/**
* @param latitude the latitude, in degrees.
* @param longitude the longitude, in degrees.
*/
public static GeoLocation fromDegrees(double latitude, double longitude) {
GeoLocation result = new GeoLocation();
result.radLat = Math.toRadians(latitude);
result.radLon = Math.toRadians(longitude);
result.degLat = latitude;
result.degLon = longitude;
result.checkBounds();
return result;
}
/**
* @param latitude the latitude, in radians.
* @param longitude the longitude, in radians.
*/
public static GeoLocation fromRadians(double latitude, double longitude) {
GeoLocation result = new GeoLocation();
result.radLat = latitude;
result.radLon = longitude;
result.degLat = Math.toDegrees(latitude);
result.degLon = Math.toDegrees(longitude);
result.checkBounds();
return result;
}
private void checkBounds() {
if (radLat < MIN_LAT || radLat > MAX_LAT ||
radLon < MIN_LON || radLon > MAX_LON)
throw new IllegalArgumentException();
}
/**
* @return the latitude, in degrees.
*/
public double getLatitudeInDegrees() {
return degLat;
}
/**
* @return the longitude, in degrees.
*/
public double getLongitudeInDegrees() {
return degLon;
}
/**
* @return the latitude, in radians.
*/
public double getLatitudeInRadians() {
return radLat;
}
/**
* @return the longitude, in radians.
*/
public double getLongitudeInRadians() {
return radLon;
}
@Override
public String toString() {
return "(" + degLat + "\u00B0, " + degLon + "\u00B0) = (" +
radLat + " rad, " + radLon + " rad)";
}
/**
* Computes the great circle distance between this GeoLocation instance
* and the location argument.
* @param radius the radius of the sphere, e.g. the average radius for a
* spherical approximation of the figure of the Earth is approximately
* 6371.01 kilometers.
* @return the distance, measured in the same unit as the radius
* argument.
*/
public double distanceTo(GeoLocation location, double radius) {
return Math.acos(Math.sin(radLat) * Math.sin(location.radLat) +
Math.cos(radLat) * Math.cos(location.radLat) *
Math.cos(radLon - location.radLon)) * radius;
}
/**
* <p>Computes the bounding coordinates of all points on the surface
* of a sphere that have a great circle distance to the point represented
* by this GeoLocation instance that is less or equal to the distance
* argument.</p>
* <p>For more information about the formulae used in this method visit
* <a href="http://JanMatuschek.de/LatitudeLongitudeBoundingCoordinates">
* http://JanMatuschek.de/LatitudeLongitudeBoundingCoordinates</a>.</p>
* @param distance the distance from the point represented by this
* GeoLocation instance. Must me measured in the same unit as the radius
* argument.
* @param radius the radius of the sphere, e.g. the average radius for a
* spherical approximation of the figure of the Earth is approximately
* 6371.01 kilometers.
* @return an array of two GeoLocation objects such that:<ul>
* <li>The latitude of any point within the specified distance is greater
* or equal to the latitude of the first array element and smaller or
* equal to the latitude of the second array element.</li>
* <li>If the longitude of the first array element is smaller or equal to
* the longitude of the second element, then
* the longitude of any point within the specified distance is greater
* or equal to the longitude of the first array element and smaller or
* equal to the longitude of the second array element.</li>
* <li>If the longitude of the first array element is greater than the
* longitude of the second element (this is the case if the 180th
* meridian is within the distance), then
* the longitude of any point within the specified distance is greater
* or equal to the longitude of the first array element
* <strong>or</strong> smaller or equal to the longitude of the second
* array element.</li>
* </ul>
*/
public GeoLocation[] boundingCoordinates(double distance, double radius) {
if (radius < 0d || distance < 0d)
throw new IllegalArgumentException();
// angular distance in radians on a great circle
double radDist = distance / radius;
double minLat = radLat - radDist;
double maxLat = radLat + radDist;
double minLon, maxLon;
if (minLat > MIN_LAT && maxLat < MAX_LAT) {
double deltaLon = Math.asin(Math.sin(radDist) /
Math.cos(radLat));
minLon = radLon - deltaLon;
if (minLon < MIN_LON) minLon += 2d * Math.PI;
maxLon = radLon + deltaLon;
if (maxLon > MAX_LON) maxLon -= 2d * Math.PI;
} else {
// a pole is within the distance
minLat = Math.max(minLat, MIN_LAT);
maxLat = Math.min(maxLat, MAX_LAT);
minLon = MIN_LON;
maxLon = MAX_LON;
}
return new GeoLocation[]{fromRadians(minLat, minLon),
fromRadians(maxLat, maxLon)};
}
}
推荐答案
选择一个默认值(弧度或度)并坚持使用.您可以编写一个类方法以自动转换为其他方法:
Chose one default ( radians or degrees ) and stick with it. You can write a classmethod to automatically convert to the other:
class geoLocation:
def __init__(self, lat, long):
"""init class from lat,long as radians"""
@classmethod
def fromDegrees(cls, dlat, dlong):
"""creat `cls` from lat,long in degrees """
return cls( to_radians(dlat), to_radians(dlong))
@classmethod
def fromRadians(cls, lat, long): # just in case
return cls(lat, long)
obj = geoLocation.fromDegrees(10,20) # returns a new geoLocation object
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