dict()和{}有什么区别? [英] What's the difference between dict() and {}?
问题描述
因此,假设我想制作一本字典.我们将其称为d
.但是有多种方法可以在Python中初始化字典!例如,我可以这样做:
So let's say I wanna make a dictionary. We'll call it d
. But there are multiple ways to initialize a dictionary in Python! For example, I could do this:
d = {'hash': 'bang', 'slash': 'dot'}
或者我可以这样做:
d = dict(hash='bang', slash='dot')
或者奇怪的是:
d = dict({'hash': 'bang', 'slash': 'dot'})
或者这个:
d = dict([['hash', 'bang'], ['slash', 'dot']])
和dict()
函数的其他多种方式.因此,显然dict()
提供的一件事是语法和初始化的灵活性.但这不是我要问的.
And a whole other multitude of ways with the dict()
function. So obviously one of the things dict()
provides is flexibility in syntax and initialization. But that's not what I'm asking about.
说我要使d
只是一个空字典.当我执行d = {}
与d = dict()
相对时,Python解释器的幕后发生了什么?是做同一件事的两种简单方法吗?使用{}
是否具有
Say I were to make d
just an empty dictionary. What goes on behind the scenes of the Python interpreter when I do d = {}
versus d = dict()
? Is it simply two ways to do the same thing? Does using {}
have the additional call of dict()
? Does one have (even negligible) more overhead than the other? While the question is really completely unimportant, it's a curiosity I would love to have answered.
推荐答案
>>> def f():
... return {'a' : 1, 'b' : 2}
...
>>> def g():
... return dict(a=1, b=2)
...
>>> g()
{'a': 1, 'b': 2}
>>> f()
{'a': 1, 'b': 2}
>>> import dis
>>> dis.dis(f)
2 0 BUILD_MAP 0
3 DUP_TOP
4 LOAD_CONST 1 ('a')
7 LOAD_CONST 2 (1)
10 ROT_THREE
11 STORE_SUBSCR
12 DUP_TOP
13 LOAD_CONST 3 ('b')
16 LOAD_CONST 4 (2)
19 ROT_THREE
20 STORE_SUBSCR
21 RETURN_VALUE
>>> dis.dis(g)
2 0 LOAD_GLOBAL 0 (dict)
3 LOAD_CONST 1 ('a')
6 LOAD_CONST 2 (1)
9 LOAD_CONST 3 ('b')
12 LOAD_CONST 4 (2)
15 CALL_FUNCTION 512
18 RETURN_VALUE
dict()显然是C内置的.一个真正聪明或专心的人(不是我)可以查看口译员的资料并告诉您更多信息.我只是想炫耀dis.dis. :)
dict() is apparently some C built-in. A really smart or dedicated person (not me) could look at the interpreter source and tell you more. I just wanted to show off dis.dis. :)
这篇关于dict()和{}有什么区别?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!