我们无法根据蚂蚁编译，但工作在命令行，为什么呢？ [英] Unable to compile from ant but works from the command line, why?

问题描述

林有麻烦提供一个类来我的项目，在这两个蚂蚁和月食。

Im having trouble making a class available to my project, in both ant and eclipse.

我使用eclipse JUNO + WPT 和蚂蚁1.7

I'm using eclipse juno+wpt, and ant 1.7.

我从信用卡公司名为CrediCard在委内瑞拉已经工作网站的整合支付plataform。

I'm integrating a payment plataform from a credit card company called CrediCard in Venezuela to an already working site.

我们收到的.zip包，其中包含以下内容：

We received a .zip package which contains the following:

林：

libc6.1-1.so.2

项目所需的运行，这我不真正了解。
也因为生产OS自身也未Debian的。

Needed for the project to run, which i dont really understand. Also because the production OS its also un debian.

包有一个名为ejemplodigest.java，与指令源的例子来编译它是这样的：

The package has a source example called ejemplodigest.java, with the instructions to compile it like this:

javac -classpath /home/DigestJavaLinux/classes ejemplodigest.java

和这样运行的：

java -Djava.library.path=/home/DigestJavaLinux/lib/ -classpath /home/DigestJavaLinux/:/home/DigestJavaLinux/classes ejemplodigest

这些命令在命令行上完美运行。要运行它依赖的 libc6.1-1.so.2 必须安装在debian的。

These commands run perfectly on the command line. To run it the dependency libc6.1-1.so.2 must be installed in debian.

如何过即时通讯无法连编译code。与蚂蚁，当我在自己的项目对应的线和类路径添加到Ant的javac任务。我得到的错误

How ever im not able to even compile the code with ant, when i include the corresponding lines in my project and add the classpath to the ant's javac task. I get the error

symbol  : class OasisEMSecIm
    [javac] location: class com.bamboo.catW3.business.impl.MainHtmlController
    [javac]          OasisEMSecIm digest= new OasisEMSecImp();

在类的声明，进口：

import OasisEM.*;
import eMerchantServlet.*;

都没有发现：

OasisEM does not exist.

这是给出的示例源：

//import OasisEM.*;
import java.*;
// import eMerchantServlet.*;

class ejemplodigest {
    public static void main(String args[]) {
        String varMerchant = "00260364";        // Merchant ID
        String varStore = "0";                  // Store ID
        String varTerm = "4001";                // Term ID
        String varTotal = "12345445";           // Monto de Transaccion
        String varCurrency = "937";             // Codigo de Moneda
        String varOrder_id = "444444";          // Order Id
        String varDigest;                       // Valor de Digest


        OasisEMSecImp digest= new OasisEMSecImp();
        varDigest = digest.getDigest(varTotal,varOrder_id,varMerchant,varStore,varTerm,varCurrency);

        System.out.println ("Merchant ID :" + varMerchant);
        System.out.println ("Store ID :" + varStore);
        System.out.println ("Term ID :" + varTerm);
        System.out.println ("Total :" + varTotal);
        System.out.println ("Currency :" + varCurrency);
        System.out.println ("Order ID :" + varOrder_id);
        System.out.println ("Digest " + varDigest);

    }
}

我不能够让Eclipse中承认他们要么，我曾尝试添加类文件夹到Eclipse，使得该类一个罐子，加入它。

I'm not able to make Eclipse recognise them either, i have tried adding the class folder to the Eclipse, making the class a jar and adding it.

我查了一下路径由Ant任务正确地接收，与所有其他依赖它做工精细。

I checked and the paths are correctly received by the ant task, with all the others dependencies which work fine.

ANT问：为什么示例源使用命令行编​​译，但添加相同的线路时，在我的项目的方法和添加类路径的类文件夹不编译

ANT Question: Why does the example source compiles with the command line, but when adding the same lines to a method in my project and adding the classpath to the class folder it does not compile ?

Eclipse的问题：我如何可以使Eclipse的识别类OasisEMSecImp

Eclipse Question: How can i make Eclipse recognise the class OasisEMSecImp ?

更新

您好，蚂蚁的文件是有点长，怎么过我会贴上我认为是相关的部分：

Hello, the ant file is a little long, how ever i'll paste what i think is the relevant part:

<path id="library.digest.classpath">
            <pathelement location="../../digest/classes"/>
        </path>

 <path id="catw.module.classpath">
        <path refid="library.blazeds.classpath"/>
        <path refid="library.hibernate3.classpath"/>
        <path refid="library.jta.classpath"/>
        <path refid="library.log4j.classpath"/>
        <path refid="library.mail.classpath"/>
        <path refid="library.oreilly.classpath"/>
        <path refid="library.spring-2.0.7.classpath"/>
        <path refid="library.velocity.classpath"/>
        <path refid="library.jexcel.classpath"/>
        <path refid="library.tomcat_5.classpath"/>
        <path refid="library.digest.classpath" />
        <pathelement location="../catw-common/build/catw-common.jar"/>
    </path>


<javac destdir="${catw.output.dir}" debug="${compiler.debug}" nowarn="${compiler.generate.no.warnings}" memorymaximumsize="${compiler.max.memory}" fork="true">
            <compilerarg line="${compiler.args.catw}"/>
            <bootclasspath refid="catw.module.bootclasspath"/>
            <classpath refid="catw.module.classpath"/>
            <src refid="catw.module.sourcepath"/>
            <patternset refid="excluded.from.compilation.catw"/>
        </javac>

我调试的catw.module.classpath和位置是否正确。

I debugged the catw.module.classpath and the location is correct.

非常感谢你在前进。

推荐答案

我已经明白这个问题，发现周围的工作我的情况，我解释一下我的<一个href=\"http://stackoverflow.com/questions/15576305/unable-to-create-jar-when-adding-the-package-declaration\">answer在这个问题上。

I have understood the problem and found a work around for my situation, i explain it in my answer in this question.

希望它可以帮助别人。

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