sscanf不移动,每次扫描相同的整数 [英] sscanf doesn't move, scanning same integer everytime
问题描述
我有一个包含整数的字符串,并且我试图将所有整数放入另一个数组中.当sscanf
找不到int
时,我希望循环停止.因此,我做了以下事情:
I have a string that has ints and I'm trying to get all the ints into another array. When sscanf
fails to find an int
I want the loop to stop. So, I did the following:
int i;
int getout = 0;
for (i = 0; i < bsize && !getout; i++) {
if (!sscanf(startbuffer, "%d", &startarray[i])) {
getout = 1;
}
}
//startbuffer is a string, startarray is an int array.
这导致startarray
的所有元素成为startbuffer
中的第一个字符.
sscanf
可以正常工作,但是它不会移动到仅停留在第一个位置的下一个int上.
This results in having all the elements of startarray
to be the first char in startbuffer
.
sscanf
works fine but it doesn't move onto the next int it just stays at the first position.
有什么想法吗?谢谢.
推荐答案
每次调用sscanf
时,都会传递相同的字符串指针.如果要移动"输入,则每次都必须移动字符串的所有字节,这对于长字符串来说很慢.此外,它将移动不会扫描的字节.
The same string pointer is passed each time you call sscanf
. If it were to "move" the input, it would have to move all the bytes of the string each time which would be slow for long strings. Furthermore, it would be moving the bytes that weren't scanned.
相反,您需要自己查询消耗的字节数和读取的值数来自己实现.使用该信息自己调整指针.
Instead, you need to implement this yourself by querying it for the number of bytes consumed and the number of values read. Use that information to adjust the pointers yourself.
int nums_now, bytes_now;
int bytes_consumed = 0, nums_read = 0;
while ( ( nums_now =
sscanf( string + bytes_consumed, "%d%n", arr + nums_read, & bytes_now )
) > 0 ) {
bytes_consumed += bytes_now;
nums_read += nums_now;
}
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