文字游戏-将输入文字转换为小写字母-Python 3.0 [英] Text Game - Convert input text to lowercase - Python 3.0

问题描述

((对于以上编辑，以上链接未回答.以上问题与我的预期用途无关.)

((In response to the above edit, this was not answered in the above link. The above question is irrelevant to my intended use.))

我读过一个类似的问题，关于将字符串转换为小写字母；

I have read a similar question about turning a string into lowercase;

如何在Python中将字符串转换为小写

我了解这是如何完美运行的，但是我自己的尝试失败了.

I understand how this works perfectly, however my attempts at this myself have failed.

这是我当前的调试块设置示例；

Here's my current setup example for a debug block;

#Debug block - Used to toggle the display of variable data throughout the game for debug purposes.
def debug():
    print("Would you like to play in Debug/Developer Mode?")
    while True:
        global egg
        choice = input()
        if choice == "yes":
            devdebug = 1
            break
        elif choice == "Yes":
            devdebug = 1
            break
        elif choice == "no":
            devdebug = 0
            break
        elif choice == "No":
            devdebug = 0
            break
        elif choice == "bunny":
            print("Easter is Here!")
            egg = 1
            break
        else:
            print("Yes or No?")
 #

因此，我已预先编写了使用其他大写字母的代码.但是，我只想每个单词只使用一个if语句，而不要使用两个大写字母.我确实有个主意，可以使用另一个代码块来确定True的False状态； <​​/p>

So, I have it prewritten to work with a different capitalization. However, I'd like to use only one if statement per word rather than using two for the capitalization. I do have an idea, that uses another block to determine a True of False state, which would look like this;

def debugstate():
    while True:
        global devstate
        choice = input()
        if choice == "Yes":
            devstate = True
            break
        elif choice == "yes":
            devstate = True
            break
        elif choice == "No":
            devstate = False
            break
#Etc Etc Etc

但是使用此块只会占用我已经拥有的代码行，然后将其移动到其他地方.我知道我可以进行设置，如果不是'Yes'，则else可以自动将devstate设置为0，但是我更喜欢具有更可控的环境.我不想不小心用空格输入'yes'并关闭devmode.

But using this block would just take the lines of code I already have, and move it somewhere else. I know I could set it up that if it isn't 'Yes' then the else can automatically set devstate to 0, but I prefer to have a more controlled environment. I don't want to accidentally type 'yes ' with a space and have devmode off.

回到问题；

我将如何做到这一点，以便我可以执行以下操作?

How would I make it so I can just do the following?

def debug():
    print("Debug Mode?")
    while True:
        global egg
        choice = input()
        if choice == "yes" or "Yes":
            devdebug = 1
            break
        elif choice == "no" or "No":
            devdebug = 0
            break
        elif choice == "egg":
            devdebug = 0
            egg = 1
            print("Easter is Here")
            break
        else:
            print("Yes or No?")
#

上面的代码可能不是最好的例子，但是当我说我每个单词只想要一个if语句时，它至少可以帮助我理解我的观点. (此外，我希望我不只是在xD上解决自己的问题.)

The above code probably isn't the best example, but it at least helps me get my point across when I say I only want one if statement per word. (Also, I hope I didn't just solve my own problem here xD.)

那么，我该怎么做?

((此外，我之所以来到这里而不是Python论坛的原因是，我更喜欢以自己的方式提出问题，而不是试图从一个措辞不同的问题中拼凑出答案).)

((Also, the reason I go here rather than the Python forums is because I prefer to ask my question in my own way rather than trying to piece together an answer from a question that was worded differently for someone else.))

推荐答案

使用.lower()是您的最佳选择

Using .lower() is your best option

choice = input()
choice = choice.lower()
if choice == 'yes':
    dev_debug = 1
    break

或使用中"

choice = input()
if choice in ('yes', 'Yes'):
    dev_debug = 1
    break

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