从URL读取InputStream并由Servlet编写 [英] Reading InputStream from URL and write it by Servlet
问题描述
我正在尝试编写一个InputStream，它是通过Servlet的doGet方法从URL获得的.这是我的代码:
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String requestedUrl = request.getParameter("url");
if (StringUtils.isNotBlank(requestedUrl)) {
ReadableByteChannel inputChannel = null;
WritableByteChannel outputChannel = null;
try {
URL url = new URL(requestedUrl);
HttpURLConnection httpConnection = (HttpURLConnection) url.openConnection();
int responseCode = httpConnection.getResponseCode();
System.out.println(responseCode);
if (responseCode == HttpURLConnection.HTTP_OK) {
response.setContentType("image/jpg");
httpConnection.connect();
InputStream imageStream = url.openStream();
OutputStream outputStream = response.getOutputStream();
inputChannel = Channels.newChannel(imageStream);
outputChannel = Channels.newChannel(outputStream);
ByteBuffer buffer = ByteBuffer.allocate(10240);
while (inputChannel.read(buffer) != -1) {
buffer.flip();
outputChannel.write(buffer);
buffer.clear();
}
}
} catch (Exception ex) {
Log.error(this, ex.getMessage(), ex);
} finally {
if (ObjectUtils.notEqual(outputChannel, null)) {
try {
outputChannel.close();
} catch (IOException ignore) {
}
}
if (ObjectUtils.notEqual(inputChannel, null)) {
try {
inputChannel.close();
} catch (IOException ignore) {
}
}
}
}
}
我可以在控制台中看到responseCode是200，但是它没有在页面中写入任何内容.在Firefox中，我得到了:
图像 "the_context_root/dam/no-image-aware-servlet?url = http％3A//localhost％3A80/file/MHIS044662& Rendition = 164FixedWidth& noSaveAs = 1" 无法显示，因为其中包含错误.
我找不到我做错了什么.任何指针都将非常有帮助.
我试图对您的代码进行一些修改，以解决getResponseCode()和connect()的错误顺序以及其他一些小问题. /p>
特别是如果出现问题(例如，在其他服务器上找不到文件，IOException，非法URL等)，请务必始终返回错误状态代码(不是2xx)，否则浏览器始终会显示200-可以，但是没有数据！
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String requestedUrl = request.getParameter("url");
if (StringUtils.isBlank(requestedUrl)) {
// TODO: send error code 400 - Bad Request
return;
}
try {
URL url = new URL(requestedUrl);
HttpURLConnection httpConnection = (HttpURLConnection) url.openConnection();
response.setContentType("image/jpg");
httpConnection.connect();
int responseCode = httpConnection.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_OK) {
// TODO: set correct content type to response
OutputStream outputStream = response.getOutputStream();
try (InputStream imageStream = url.openStream()) {
IOUtils.copy(imageStream, outputStream );
}
} else {
// TODO: send error code (depends on responseCode), probably 500
}
} catch (Exception ex) {
Log.error(this, ex.getMessage(), ex);
// TODO: send error code 400 if malformed url
// TODO: send error code 404 if image not found (responseCode == 404)
// TODO: send error code 500 else
}
// Don't close the response-OutputStream! You didn't open it either!
}
I am trying to write an InputStream, which I get from an URL by the doGet method of Servlet. Here is my code:
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String requestedUrl = request.getParameter("url");
if (StringUtils.isNotBlank(requestedUrl)) {
ReadableByteChannel inputChannel = null;
WritableByteChannel outputChannel = null;
try {
URL url = new URL(requestedUrl);
HttpURLConnection httpConnection = (HttpURLConnection) url.openConnection();
int responseCode = httpConnection.getResponseCode();
System.out.println(responseCode);
if (responseCode == HttpURLConnection.HTTP_OK) {
response.setContentType("image/jpg");
httpConnection.connect();
InputStream imageStream = url.openStream();
OutputStream outputStream = response.getOutputStream();
inputChannel = Channels.newChannel(imageStream);
outputChannel = Channels.newChannel(outputStream);
ByteBuffer buffer = ByteBuffer.allocate(10240);
while (inputChannel.read(buffer) != -1) {
buffer.flip();
outputChannel.write(buffer);
buffer.clear();
}
}
} catch (Exception ex) {
Log.error(this, ex.getMessage(), ex);
} finally {
if (ObjectUtils.notEqual(outputChannel, null)) {
try {
outputChannel.close();
} catch (IOException ignore) {
}
}
if (ObjectUtils.notEqual(inputChannel, null)) {
try {
inputChannel.close();
} catch (IOException ignore) {
}
}
}
}
}
I can see in console that the responseCode is 200 but it is not writing anything in the page. In Firefox I am getting:
The image "the_context_root/dam/no-image-aware-servlet?url=http%3A//localhost%3A80/file/MHIS044662&Rendition=164FixedWidth&noSaveAs=1" cannot be displayed because it contains errors.
I am unable to find what I am doing wrong. Any pointer would be very helpful.
I've tried to modify your code a little bit to address the wrong order of getResponseCode() and connect() as well as some other minor issues.
Especially make sure to ALWAYS return an error status code (other than 2xx) if something goes wrong (e.g. file not found on other server, IOException, illegal URL, ...), otherwise the browser always gets 200 - OK but no data!
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String requestedUrl = request.getParameter("url");
if (StringUtils.isBlank(requestedUrl)) {
// TODO: send error code 400 - Bad Request
return;
}
try {
URL url = new URL(requestedUrl);
HttpURLConnection httpConnection = (HttpURLConnection) url.openConnection();
response.setContentType("image/jpg");
httpConnection.connect();
int responseCode = httpConnection.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_OK) {
// TODO: set correct content type to response
OutputStream outputStream = response.getOutputStream();
try (InputStream imageStream = url.openStream()) {
IOUtils.copy(imageStream, outputStream );
}
} else {
// TODO: send error code (depends on responseCode), probably 500
}
} catch (Exception ex) {
Log.error(this, ex.getMessage(), ex);
// TODO: send error code 400 if malformed url
// TODO: send error code 404 if image not found (responseCode == 404)
// TODO: send error code 500 else
}
// Don't close the response-OutputStream! You didn't open it either!
}
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