在存在相似之处的Pandas系列中插入多个元素 [英] Insert multiple elements into Pandas Series where similarities exist
本文介绍了在存在相似之处的Pandas系列中插入多个元素的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在这里,我想在标签中有两行带有"href"的行之间插入行"<td class='test'>None</td>"
-请注意,带有href的每一行都不相同.
Here I'd like to insert the row "<td class='test'>None</td>"
between wherever there are two rows with "href" in the tag--note, each row with href is NOT identical.
import pandas as pd
table = pd.Series(
["<td class='test'><a class='test' href=...", # 0
"<td class='test'>A</td>", # 1
"<td class='test'><a class='test' href=...", # 2
"<td class='test'>B</td>", # 3
"<td class='test'><a class='test' href=...", # 4
"<td class='test'><a class='test' href=...", # 5
"<td class='test'>C</td>", # 6
"<td class='test'><a class='test' href=...", # 7
"<td class='test'>F</td>", # 8
"<td class='test'><a class='test' href=...", # 9
"<td class='test'><a class='test' href=...", # 10
"<td class='test'>X</td>"]) # 11
insertAt = []
for i in range(0, len(table)):
if 'href' in table[i] and 'href' in table[i+1]:
print(i + 1, ' is duplicated')
insertAt.append(i)
# 5 is duplicated
# 10 is duplicated
# [4, 9]
这是输出的外观:
# ["<td class='test'><a class='test' href=...", # 0
# "<td class='test'>A</td>", # 1
# "<td class='test'><a class='test' href=...", # 2
# "<td class='test'>B</td>", # 3
# "<td class='test'><a class='test' href=...", # 4
# "<td class='test'>None</td>", # 5 Insert "<td class='test'>None</td>"
# "<td class='test'><a class='test' href=...", # 6
# "<td class='test'>C</td>", # 7
# "<td class='test'><a class='test' href=...", # 8
# "<td class='test'>F</td>", # 9
# "<td class='test'><a class='test' href=...", # 10
# "<td class='test'>None</td>", # 11 Insert <td class='test'>None</td>"
# "<td class='test'><a class='test' href=...", # 12
# "<td class='test'>X</td>"] # 13
推荐答案
如果您使用numpy,可以轻松实现.
Than can be easily achieved if you go to numpy.
在您的示例中:
dups = table.str.contains('href') & table.shift(1).str.contains('href')
array = np.insert(table.values, dups[dups].index, "<td class='test'>None</td>")
pd.Series(array)
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