我如何从Twitter实体获取直接的Instagram链接? [英] How can I get an direct Instagram link from a twitter entity?

问题描述

我有一个Twitter提要，我可以在一条推文中找到instagram网址.

I have a twitter feed and I can find the instagram url in a tweet.

{
    indices: [
        90,
        110
    ],
    url: "http://t.co/kF9EXifn",
    expanded_url: "http://instagr.am/p/QC8hWKL_4K/",
    display_url: "instagr.am/p/QC8hWKL_4K/"
}

我需要从该对象"http://instagr.am/p/QC8hWKL_4K/"中获取展开的网址，并获得指向仅图像本身而不是图像上的链接. Instagram网站.有人知道该怎么做吗?我什至可以从网址中获取该链接吗?

What I need is to take the expanded url from that object "http://instagr.am/p/QC8hWKL_4K/" and get the link to just the image itself, not the image on the Instagram site. Anyone know how to do that? Can I even derive the that link from the url?

推荐答案

您可以通过将/media/附加到URL来仅获取图像.使用您的示例: http://instagr.am/p/QC8hWKL_4K/media/.

You can get just the image by appending /media/ to the URL. Using your example: http://instagr.am/p/QC8hWKL_4K/media/.

您甚至可以指定大小

t(缩略图)，m(中)，l(大)之一.默认为m.

One of t (thumbnail), m (medium), l (large). Defaults to m.

对于缩略图: http://instagr.am/p/QC8hWKL_4K/media/?size = t

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