检测以相同名称运行的进程数 [英] Detect number of processes running with the same name

问题描述

关于如何编写一个返回正在运行的进程实例数的函数的想法吗?

Any ideas of how to write a function that returns the number of instances of a process is running?

也许是这样吗?

function numInstances([string]$process)
{
    $i = 0
    while(<we can get a new process with name $process>)
    {
        $i++
    }

    return $i
}

开始编写函数...它适用于单个实例，但如果有多个实例在运行，它将陷入无限循环:

Started to write a function... It works for a single instance but it goes into an infinite loop if more than one instance is running:

function numInstances([string]$process)
{
$i = 0
$ids = @()
while(((get-process $process) | where {$ids -notcontains $_.ID}) -ne $null)
    {
    $ids += (get-process $process).ID
    $i++
    }

return $i
}

推荐答案

function numInstances([string]$process)
{
    @(get-process -ea silentlycontinue $process).count
}

编辑:添加了静默继续和数组强制转换，以使用零个和一个进程.

EDIT: added the silently continue and array cast to work with zero and one processes.

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