如何在Ruby中将浮点十进制值转换为整数 [英] How to turn float decimal values into integers in ruby

问题描述

如何获取浮点数的十进制值并将其转换为ruby中的整数?

How can one get the decimal values of a float and turn it into an integer in ruby?

这是我到目前为止所走的距离:

Here is how far I got so far:

number = 12.55
decimal_length = number.to_s.split('.')[1].size #=> 2 
decimal = number.divmod(1)[1].round(decimal_length) #=> 0.55

这里如何将小数转换为整数(55)，使其可以与任何数字作为输入?

Here how can I turn decimal into integer (55) in a way that it would work with any number as input?

推荐答案

也许我误会了?但是您已经知道，您只是在做额外的工作.

Maybe I'm misunderstanding? But you've got it you're just doing extra work.

number = 12.55
number.to_s.split('.')[1].to_i
#  => 55 

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