接口Java1.8中的具体方法 [英] concrete methods in interfaces Java1.8

问题描述

在讨论中，我的一位朋友告诉我concrete methods would be allowed in java 1.8 in interfaces，那时我想到一个问题，即如果允许，那么我们将如何区分这些方法.例如
我有两个接口Animal.java和Pet.java，并且都具有相同的具体方法，即eat()

During a discussion one of my friend tell me that concrete methods would be allowed in java 1.8 in interfaces then at that time a question came into my mind i-e If they are allowed then How will we distinguish the methods.For example
I have two Interface Animal.java and Pet.java and both have same concrete method i-e eat()

   public interfaces Animal{

        void eat(){
                System.out.println("Animal Start eating ....");
        }
   }

   public interfaces Pet{

        void eat(){
                System.out.println("Pet Start eating ....");
        }
   }

现在，我的Zoo.java都实现了这两个功能，并且没有覆盖

Now my Zoo.java implement both of these and didn't override

    public class Zoo() implements Pet , Animal{ 
             //Now name method is a part of this class
   }

现在这是我的困惑.如何使用Test对象

Now here is my confusion.How can I call a specific method on inteface animal using Test object

public class Demo{
        public static void main(String[] args){

                 Zoo zoo = new Zoo();
                 zoo.eat();    //What would be the output
        }
 }

有什么建议吗?还是在java1.8中对此有任何解决方案，因为我找不到答案?

Any suggestions? or is there any solution for this in java1.8 as I am unable to find its answer.

推荐答案

除非您在Zoo类中覆盖eat，否则您会收到编译时错误.

You get a compile time error, unless you override eat in your Zoo class.

java: class defaultMethods.Zoo inherits unrelated defaults for eat() from types Pet and Animal

最新，最漂亮的jdk是此处btw .语法应该是

The latest and geatest jdk is here btw. And the syntax should be

default void eat(){
  System.out.println("Animal Start eating ....");
}

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