Python3:检查方法是否静态 [英] Python3: check if method is static

问题描述

Simmilar问题(与Python2相关: Python:检查方法是否静态)

Simmilar question (related with Python2: Python: check if method is static)

让我们考虑以下类定义:

Lets concider following class definition:

class A:
  def f(self):
    return 'this is f'

  @staticmethod
  def g():
    return 'this is g'

在Python 3中，不再有instancemethod，一切都正常了，因此与Python 2相关的答案将不再起作用.

In Python 3 there is no instancemethod anymore, everything is function, so the answer related to Python 2 will not work anymore.

正如我所说的，一切都是函数，因此我们可以调用A.f(0)，但是我们当然不能调用A.f()(参数不匹配).但是，如果我们创建实例a=A()并调用a.f()，则Python将第一个参数传递给函数A.f，self.调用a.g()会阻止发送它或捕获self-因此必须有一种方法来测试它是否为静态方法.

As I told, everything is function, so we can call A.f(0), but of course we cannot call A.f() (argument missmatch). But if we make an instance a=A() and we call a.f() Python passes to the function A.f the self as first argument. Calling a.g() prevents from sending it or captures the self - so there have to be a way to test if this is staticmethod or not.

那么我们可以在Python3中检查某个方法是否声明为static吗?

So can we check in Python3 if a method was declared as static or not?

推荐答案

class A:
  def f(self):
    return 'this is f'

  @staticmethod
  def g():
    return 'this is g'
print(type(A.__dict__['g']))
print(type(A.g))

<class 'staticmethod'>
<class 'function'>

这篇关于Python3:检查方法是否静态的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！