团结不需要任何登记就能使事情变得轻松吗? [英] Does unity just make clasess with out needing anything registered?

问题描述

我正在观看Mike Tautly关于Prism的精彩介绍.一切都说得通，但是在第六个视频中我有些困惑.

I am watching Mike Tautly's awesome intro to Prism. It was all making sense, but I got a bit confused in the sixth video.

他让他的视图类的构造函数采用ViewModel的参数.然后他说团结将为我们填充(即构建它).

He has his view class's constructor take a parameter of the ViewModel. He then says that unity will fill this in for us (ie construct it).

过去，他不得不注册这种东西(即，将MyyClass注册到MyClass).但是他没有为ViewModel做到这一点.

In the past he has had to register this kind of thing (ie IMyClass registered to MyClass). But he did not do that for the ViewModel.

我能看到的唯一区别是对ViewModel的依赖不是接口，而是直接类.团结会看到这一点，只是尝试构建ViewModel还是错过了一步? (如果ViewModel有参数，它也会尝试做那些吗?)

The only difference I can see is that the dependency to the ViewModel was not an interface, but rather a direct class. Does unity see that and just try to construct the ViewModel or did I miss a step? (And if the ViewModel had parameters would it try to make those too?)

推荐答案

可以实例化一个类型(即不是基类也不是接口)时，Unity可以找出如何创建该类型而无需注册类型映射

When a type can be instantiated (i.e. not a base class nor an interface) unity can figure out how that type is created without the need of registering a type mapping.

当要注入的类型无法单独实例化时，映射很有用.

Mappings are useful when the type to be injected is not instantiatable on its own.

我希望这会有所帮助.

谢谢， 达米安

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