离子3:从PlayStore链接获取价值 [英] Ionic 3: Getting value from PlayStore link

问题描述

我有一个Ionic 3应用，我想根据Playstore的下载链接在其中设置一些变量. 例如，http://linktoplaystore.com/app?account=4会将我的应用程序内的account变量设置为4.有什么方法可以实现?

I have an Ionic 3 app and I want to set some variable inside it based on the download link from Playstore. For example, http://linktoplaystore.com/app?account=4 would set the account variable inside my app to be 4. Is there any way to achieve this?

推荐答案

我终于设法使用Firebase动态链接使它正常工作.

I finally managed to make it work using Firebase Dynamic Links.

在Firebase控制台中设置我的应用程序后，我手动创建了一个看起来像这样的链接:

After I've setup my app in the Firebase console, I manually created a link which looks like this:

https://myapp.page.link/?link=https://play.google.com/store/apps/details?id=com.ionicframework.myapp?account4

在我的Ionic应用程序中，我已经安装并配置了Firebase Dynamic Links插件: https://ionicframework.com/docs/native/firebase-dynamic-links/

In my Ionic app, I've installed and configured Firebase Dynamic Links plugin: https://ionicframework.com/docs/native/firebase-dynamic-links/

然后，在app.component.ts内部，在平台初始化之后，我使用以下代码:

Then, inside app.component.ts, after the platform is initialized, I use this code:

firebaseDynamicLinks.onDynamicLink().subscribe((res: any) => {
 let link = res;
}, err => {
  alert(err);
});

该链接将是一个如下所示的JavaScript对象:

The link will be a JavaScript object that looks like this:

{"deepLink":"https://play.google.com/store/apps/details?id=com.ionicframework.couriermanagerclient1234?account4","clickTimestamp":1535449992657,"minimumAppVersion":0}

从这里，我可以解析结果并从deepLink属性内部提取account参数

From here, I can parse the result and extract the account parameter from inside the deepLink property

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