在Swift中格式化电话号码 [英] Formatting Phone number in Swift
本文介绍了在Swift中格式化电话号码的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
一旦用户开始将电话号码键入此格式类型0 (555) 444 66 77
,我正在格式化文本文件中的文本,并且可以正常工作,但是一旦我从服务器上获取了电话号码,就可以像这样05554446677
您告诉我,一旦从服务器上获得该文件,该如何以相同的格式对其进行编辑?
I'm formatting my textfiled text once the user start typing the phone number into this format type 0 (555) 444 66 77
and it is working fine but once I get the number from the server I get it like this 05554446677
So please could you tell me how I can edit it in the same format once I get it fro the server?
我的代码开始输入后会显示:
My code once I start typing:
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
if textField == phoneNumberTextField{
var newString = (textField.text as NSString).stringByReplacingCharactersInRange(range, withString: string)
var components = newString.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet)
var decimalString = "".join(components) as NSString
var length = decimalString.length
var hasLeadingOne = length > 0 && decimalString.characterAtIndex(0) == (1 as unichar)
if length == 0 || (length > 11 && !hasLeadingOne) || length > 12{
var newLength = (textField.text as NSString).length + (string as NSString).length - range.length as Int
return (newLength > 11) ? false : true
}
var index = 0 as Int
var formattedString = NSMutableString()
if hasLeadingOne{
formattedString.appendString("1 ")
index += 1
}
if (length - index) > 1{
var zeroNumber = decimalString.substringWithRange(NSMakeRange(index, 1))
formattedString.appendFormat("%@ ", zeroNumber)
index += 1
}
if (length - index) > 3{
var areaCode = decimalString.substringWithRange(NSMakeRange(index, 3))
formattedString.appendFormat("(%@) ", areaCode)
index += 3
}
if (length - index) > 3{
var prefix = decimalString.substringWithRange(NSMakeRange(index, 3))
formattedString.appendFormat("%@ ", prefix)
index += 3
}
if (length - index) > 3{
var prefix = decimalString.substringWithRange(NSMakeRange(index, 2))
formattedString.appendFormat("%@ ", prefix)
index += 2
}
var remainder = decimalString.substringFromIndex(index)
formattedString.appendString(remainder)
textField.text = formattedString as String
return false
}else{
return true
}
}
推荐答案
使用String中的字符进行操作不是很简单.您需要执行以下操作:
Manipulations with characters in String are not very straightforward. You need following:
Swift 2.1
let s = "05554446677"
let s2 = String(format: "%@ (%@) %@ %@ %@", s.substringToIndex(s.startIndex.advancedBy(1)),
s.substringWithRange(s.startIndex.advancedBy(1) ... s.startIndex.advancedBy(3)),
s.substringWithRange(s.startIndex.advancedBy(4) ... s.startIndex.advancedBy(6)),
s.substringWithRange(s.startIndex.advancedBy(7) ... s.startIndex.advancedBy(8)),
s.substringWithRange(s.startIndex.advancedBy(9) ... s.startIndex.advancedBy(10))
)
Swift 2.0
let s = "05554446677"
let s2 = String(format: "%@ (%@) %@ %@ %@", s.substringToIndex(advance(s.startIndex, 1)),
s.substringWithRange(advance(s.startIndex, 1) ... advance(s.startIndex, 3)),
s.substringWithRange(advance(s.startIndex, 4) ... advance(s.startIndex, 6)),
s.substringWithRange(advance(s.startIndex, 7) ... advance(s.startIndex, 8)),
s.substringWithRange(advance(s.startIndex, 9) ... advance(s.startIndex, 10))
)
将打印代码
0 (555) 444 66 77
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