iOS-如何通过触摸视图外部的任何位置来隐藏视图 [英] IOS - How to hide a view by touching anywhere outside of it

问题描述

我是IOS编程的新手，单击按钮时会在按钮方法中使用以下代码来显示视图.

I'm new to IOS programming, I'm displaying a view when a button is clicked, using the following code inside the button method.

 @IBAction func moreButton(_ sender: Any)
    {
        self.helpView.isHidden = false
    }

最初，

在viewDidLoad方法中将self.helpView.isHidden设置为true以隐藏视图.现在，我如何通过触摸视图外部的任何位置来消除该视图.通过研究，我发现可以通过创建适合整个viewController的透明按钮来完成此操作.因此，通过单击按钮，我们可以关闭视图.任何人都可以快速地给我代码3来创建这样的按钮.

initially, the self.helpView.isHidden is set to true in viewDidLoad method to hide the view. Now, how can i dismiss this view by touching anywhere outside the view. From the research, i found that, it can be done by creating a transparent button that fits the whole viewController. So then by clicking on the button, we can make the view to dismiss. Can anyone give me the code in swift 3 to create such button.

或者，如果还有其他更好的隐藏视图的方法，那就欢迎它.

Or, if there is any other better way to hide a view, it is welcomed.

我正在使用Xcode 8.2，swift 3.0

I'm using Xcode 8.2, swift 3.0

谢谢.

推荐答案

开始联系时，你应该这样写

In touch began you should write like

override func touchesBegan(_ touches: Set<AnyHashable>, withEvent event: UIEvent) {
    var touch: UITouch? = touches.first
    //location is relative to the current view
    // do something with the touched point
    if touch?.view != yourView {
        yourView.isHidden = true
    }
}

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