Python识别字符串中的IP [英] Python Recognizing An IP In A String

问题描述

我在这段代码上遇到了很多麻烦:

I'm having a lot of trouble with this segment of code:

    command = "!ip"
    string = "!ip 127.0.0.1"

    if command in string:

那就是我被困住的地方.在第一个if语句之后，我需要另一个来识别任何IP地址，而不是127.0.0.1.最简单的方法是什么?

That's where I get stuck. After the first if statement I need another one to recognize any IP address just not 127.0.0.1. What's the easiest way of doing this?

推荐答案

我会使用正则表达式来尝试一下，其中正则表达式(?:[0-9]{1,3}\.){3}[0-9]{1,3}是IP地址的简单匹配.

I would give it a shot using regular expressions, where the regular expression (?:[0-9]{1,3}\.){3}[0-9]{1,3} is a simple match for an IP address.

    ip = '127.0.0.1'

    match = re.search(r'(?:[0-9]{1,3}\.){3}[0-9]{1,3}', ip)
    # Or if you want to match it on it's own line.
    # match = re.search(r'^(?:[0-9]{1,3}\.){3}[0-9]{1,3}$', ip)

    if match:                      
         print "IP Address: %s" %(match.group)
    else:
         print "No IP Address"

使用正则表达式可以使数据匹配更轻松.

Regular expressions will make your life much easier when doing data matching.

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