检查IP地址是否在给定范围内 [英] Checking if IP address lies within a given range

问题描述

我想检查IP 180.179.77.11是否在特定范围内，例如180.179.0.0 - 180.179.255.255.

I want to check if IP 180.179.77.11 lies between a particular range, say 180.179.0.0 - 180.179.255.255.

我编写了一个函数，该函数将每个IP八位字节与其他八位字节进行比较.

I wrote a function which will compare every IP octet with the others.

def match(mask, IP):
    min_ip = mask.split(' - ')[0].split('.')
    max_ip = mask.split(' - ')[1].split('.')
    ip = IP.split('.')
    for i in range(4):
        print ip[i] + " < " + min_ip[i] + " or " + ip[i] + " > " + max_ip[i]
        print ip[i] < min_ip[i] or ip[i] > max_ip[i]
        if ip[i] < min_ip[i] or ip[i] > max_ip[i]:
            return False
    return True


match("180.179.0.0 - 180.179.255.255", "180.179.77.11")

输出:

180 < 180 or 180 > 180
False
179 < 179 or 179 > 179
False
77 < 0 or 77 > 255  # 77 > 255 is true
True
False

但是，它似乎无法正常工作；在比较77和255时，似乎在第三个八位位组中出现了问题.

However, it doesn't seem to work properly; It looks like the problem occurred in the 3rd octet while comparing 77 with 255.

我已经写了一些打印说明来说明问题区域.

I have put some print statements to illustrate the problem area.

推荐答案

您要比较的是字符串值(按词典顺序进行比较)，而不是每个IP的int值，请将它们与理解力:

You are comparing strings values (which compare lexicographically) and not the int values for every IP, make them into ints with comprehensions:

min_ip = [int(i) for i in mask.split(' - ')[0].split('.')]
max_ip = [int(i) for i in mask.split(' - ')[1].split('.')]
ip = [int(i) for i in IP.split('.')]

最好不要对mask中的每个IP进行两次拆分.先分手:

It's also best if you don't perform the split twice for every ip in mask; split before hand:

s = mask.split(' - ')
min_ip, max_ip = [[int(i) for i in j.split('.')] for j in s]

如果将enumerate与ip一起使用，则可以说for循环会更好:

Your for loop could arguably be better if you used enumerate with ip:

for ind, val in enumerate(ip):
    if val < min_ip[ind] or val > max_ip[ind]:
        return False

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