使用前导0填充IP地址-Powershell [英] Pad IP addresses with leading 0's - powershell

问题描述

我想用0填充IP地址

示例
1.2.3.4-> 001.002.003.004
50.51.52.53-> 050.051.052.053

example
1.2.3.4 -> 001.002.003.004
50.51.52.53 -> 050.051.052.053

尝试过:

[string]$paddedIP = $IPvariable
[string]$paddedIP.PadLeft(3, '0')

也尝试过拆分，但是我是Powershell的新手...

Also tried split as well, but I'm new to powershell...

推荐答案

您可以使用.Split()和-join的组合.

('1.2.3.4'.Split('.') | 
    ForEach-Object {$_.PadLeft(3,'0')}) -join '.'

使用这种方法，您一直都在使用字符串. Split('.')在每个.字符处创建一个数组元素. .PadLeft(3,'0')如有必要，确保3个字符的前导零. -join '.'将数组组合成一个字符串，每个元素用.分隔.

With this approach, you are working with strings the entire time. Split('.') creates an array element at every . character. .PadLeft(3,'0') ensures 3 characters with leading zeroes if necessary. -join '.' combines the array into a single string with each element separated by a ..

您可以使用格式运算符-f采取类似的方法.

You can take a similar approach with the format operator -f.

"{0:d3}.{1:d3}.{2:d3}.{3:d3}" -f ('1.2.3.4'.Split('.') |
    Foreach-Object { [int]$_ } )

:dN格式的字符串启用N(数字位数)以前导零填充.

The :dN format string enables N (number of digits) padding with leading zeroes.

这种方法会像第一个解决方案一样创建一个字符串数组.然后，将每个元素进行流水线处理并转换为[int].最后，将格式应用于每个元素.

This approach creates a string array like in the first solution. Then each element is pipelined and converted to an [int]. Lastly, the formatting is applied to each element.

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